Question

我正在使用Python（OSX Python 2.7.10）ssh进入Debian盒（Python 2.7.9），然后运行bash脚本（./capture）。 bash脚本包含一些tcpdump命令。我无法弄清的问题是如何在终端上显示正在运行的bash脚本的实时结果。

#!/usr/bin/env python3
import subprocess, os
output = subprocess.run(["ssh", "ju@192.168.199.125", "sudo ./capture"])
print(output)

我能够ssh，并成功运行脚本，但是没有任何输出。当我按CTRL C时，得到以下跟踪：

**^CTraceback (most recent call last):
  File "/Users/junesjoseph/run.py", line 3, in <module>
    output = subprocess.run(["ssh", "junes@192.168.199.125", "sudo ./capture"])
  File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/subprocess.py", line 405, in run
    stdout, stderr = process.communicate(input, timeout=timeout)
  File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/subprocess.py", line 835, in communicate
    self.wait()
  File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/subprocess.py", line 1457, in wait
    (pid, sts) = self._try_wait(0)
  File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/subprocess.py", line 1404, in _try_wait
    (pid, sts) = os.waitpid(self.pid, wait_flags)
KeyboardInterrupt**

任何帮助将不胜感激。谢谢

Answer 1

subprocess.run返回的对象是CompletedProcess对象，其对象包含完成的过程的stdout和stderr。您不想直接打印它，但是可以使用它来获取要打印的属性。

import subprocess  # no reason to import os
subssh = subprocess.run(["ssh", "ju@192.168.199.125", "sudo ./capture"],
    # Set up for capturing stdout and stderr
    stdout=subprocess.PIPE, stderr=subprocess.PIPE,
    # Add commonly useful attributes
    check=True, universal_newlines=True)
print(subssh.output)

如果您真的只希望将输出显示在标准输出上，则对其进行捕获以进行打印基本上是多余的。只需将其设置为直接显示即可，只需不将stdout或stderr设置为任何值即可。

subssh = subprocess.run(["ssh", "ju@192.168.199.125", "sudo ./capture"],
    # Don't set up for capturing -- leave stdout and stderr alone
    check=True, universal_newlines=True)

也许也请参见Running Bash commands in Python，其中我发布了有关subprocess常见问题的更详细的答案。

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1 个答案: