Question

我正在尝试创建一个向加入服务器的用户打招呼的机器人。但是要做到这一点，以便在服务器本身而不是在DM中向人们打招呼（我发现的大多数教程都教您如何做）。

这是我到目前为止提出的。

@bot.event
async def on_member_join(member):
    channel = bot.get_channel("channel id")
    await bot.send_message(channel,"welcome")

但是，它不起作用，而是抛出此错误。

Ignoring exception in on_member_join
Traceback (most recent call last):
File "C:\Users\Lenovo\AppData\Local\Programs\Python\Python36\lib\site- 
packages\discord\client.py", line 307, in _run_event
yield from getattr(self, event)(*args, **kwargs)
File "C:\Users\Lenovo\Documents\first bot\bot.py", line 26, in 
on_member_join
await bot.send_message(channel,"welcome")
File "C:\Users\Lenovo\AppData\Local\Programs\Python\Python36\lib\site- 
packages\discord\client.py", line 1145, in send_message
channel_id, guild_id = yield from self._resolve_destination(destination)
File "C:\Users\Lenovo\AppData\Local\Programs\Python\Python36\lib\site- 
packages\discord\client.py", line 289, in _resolve_destination
raise InvalidArgument(fmt.format(destination))
discord.errors.InvalidArgument: Destination must be Channel, PrivateChannel, 
User, or Object. Received NoneType

Answer 1

您没有将正确的ID传递给get_channel，因此它返回了None。一种快速的获取方法是调用命令

from discord.ext import commands

bot = commands.Bot(command_prefix='!')

@bot.command(pass_context=True)
async def get_id(ctx):
    await bot.say("Channel id: {}".format(ctx.message.channel.id))

bot.run("TOKEN")

您还可以修改命令，以始终在Member加入的服务器上以特定名称发布在频道中

from discord.utils import get

@bot.event
async def on_member_join(member):
    channel = get(member.server.channels, name="general")
    await bot.send_message(channel,"welcome")

Answer 2

帕特里克·豪（Patrick Haugh）的答案可能是您最好的选择，但请记住以下几点。

Member对象包含行会（服务器）以及服务器包含的文本通道。通过使用member.guild.text_channels，即使服务器没有“常规”聊天，您也可以确保该频道将存在。

@bot.event
async def on_member_join(member):
    channel = member.guild.text_channels[0]
    await channel.send('Welcome!')

Answer 3

尝试一下：

@bot.event
async def on_member_join(member):
    channel = discord.utils.get(member.guild.channels, name='the name of the channel')
    await channel.send(f'Enjoy your stay {member.mention}!')

使用discord.py欢迎/再见

3 个答案: