我为我的妻子珠宝网站创建了一个数据库。当我尝试从数据库中收集产品页面的信息时,我只能获取我放入数据库中的最后一个项目。我最初是从教程中获得代码的,因此必须对其进行处理才能获得所有项目。基本上,我需要访问所有产品,但是我只能得到一个。有人可以告诉我我所缺少的吗?
显示项目的代码:
$id = '';
if( isset( $_GET['id'])) {
$id = $_GET['id'];
}
$sql = "SELECT * FROM products WHERE category = 'Accessories'";
$result = mysqli_query($con, $sql);
$resultCheck = mysqli_num_rows($result);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $item_number = $row["item_number"];
$price = $row["price"];
$desc = $row["description"];
$category = $row["category"];
}
}
这是表格的代码:
<table width="100%" border="2" cellspacing="0" cellpadding="15">
<tr>
<td width="19%" valign="top"><img src="pictures/inventory/<?php echo $pid; ?>.jpg" width="142" height="188" alt="<?php echo $item_number; ?>" /><br />
<a href="pictures/inventory/<?php echo $pid; ?>.pngjpg">View Full Size Image</a>
</td>
<td width="81%" valign="top">
<h3 class="Item"><?php echo $item_number; ?></h3>
<p>
<?php echo "$".$price; ?>
<br />
<br />
<?php echo $desc; ?>
<br />
</p>
<form id="form1" name="form1" method="post" action="cart.php">
<input type="hidden" name="pid" id="pid" value="<?php echo $pid; ?>" />
<input class="button" type="submit" name="button" id="button" value="Add to Shopping Cart" />
</form>
</td>
</tr>
</table>
答案 0 :(得分:0)
基本解决方案: 尝试将数据分配给数组而不是像这样的变量:
while($row = $result->fetch_assoc()) {
$item_number[] = $row["item_number"];
$price[] = $row["price"];
$desc[] = $row["description"];
$category[] = $row["category"];
}
,然后使用for来显示HTML表,如下所示:
<?php
for ($i=0; $i <sizeof($item_number) ; $i++) {
?>
<table width="100%" border="2" cellspacing="0" cellpadding="15">
<tr>
<td width="19%" valign="top"><img src="pictures/inventory/<?php echo $item_number[$i]; ?>.jpg" width="142" height="188" alt="<?php echo $item_number[$i]; ?>" /><br />
<a href="pictures/inventory/<?php echo $item_number[$i]; ?>.pngjpg">View Full Size Image</a></td>
<td width="81%" valign="top"><h3 class="Item"><?php echo $item_number[$i]; ?></h3>
<p><?php echo "$".$price[$i]; ?><br />
<br />
<?php echo $desc[$i]; ?>
<br />
</p>
<form id="form1" name="form1" method="post" action="cart.php">
<input type="hidden" name="pid" id="pid" value="<?php echo $item_number[$i]; ?>" />
<input class="button" type="submit" name="button" id="button" value="Add to Shopping Cart" />
</form>
</td>
</tr>
</table>
<?php
}
?>
我用$ item_number [$ i]替换了您的$ pid。
答案 1 :(得分:0)
假设您尝试显示所有项目。您可以使用一个函数为所有项目生成html,并在函数外部声明一个包含所有html的变量。然后,您可以在页面的任何地方回显该信息。
<?php
function generateTableHtml() {
$tableHtml = '<table width="100%" border="2" cellspacing="0" cellpadding="15">';
while($row = $result->fetch_assoc()) {
$tableHtml .= '<tr>';
$tableHtml .= '<td width="19%" valign="top">';
$tableHtml .= '<img src="pictures/inventory/' . $row['item_number'] . '.jpg" width="142" height="188" alt="' . $row['item_number'] . '" /><br />';
$tableHtml .= '<a href="pictures/inventory/' . $row['item_number'] '.pngjpg">View Full Size Image</a></td>';
$tableHtml .= '<td width="81%" valign="top"><h3 class="Item">' . $row['item_number'] . '</h3>';
$tableHtml .= '<p>' . $row['price'] . '<br/><br/>';
$tableHtml .= $row['description'];
$tableHtml .= '<br />';
$tableHtml .= '</p>';
$tableHtml .= '<form id="form1" name="form1" method="post" action="cart.php">';
$tableHtml .= '<input type="hidden" name="pid" id="pid" value="'. $pid . '" />'
$tableHtml .= '<input class="button" type="submit" name="button" id="button" value="Add to Shopping Cart" />';
$tableHtml .= '</form>';
$tableHtml .= '</td>';
$tableHtml .= '</tr>';
}
$tableHtml .= '<table>';
return $tableHtml;
}
$tableHtml = generateTableHtml();
?>
<!-- the rest of your html -->
<?php echo $tableHtml; ?>