我开始涉猎Express,他们具有中间件的这一功能,此刻我正在探索。
因此,假设我有2个端点(/middlewaredemoa
,/middlewaredemob
),它们都需要一些不同的初始处理。然后他们有一个通用的中间件,无论最初的终点如何,都适用于相同的处理方式。
我不确定在使用GET()提供响应时执行的操作是否正确。在我看来,如果我有2个不同的终结点,则它们各自需要自己的app.get("/middlewaredemoa", ...)
。一定是这样吗?假设我只是对变量进行某种处理,然后我需要以它最终处于的任何状态返回该var,我仍然最好为每个端点定义1个get()吗?
let response = ""
app.use('/middlewaredemoa', (req, resp, next) => {
response = "Greetings from: M1a"
if ( Math.floor((Math.random() * 10) + 1) >=4){
console.log("M1a gets req and passes it on to two")
next()
} else {
throw "ARRRRRRRRRRRRRGGGGHHHHHH!"
}
})
app.use('/middlewaredemob', (req, resp, next) => {
response = "Greetings from: M1b"
if ( Math.floor((Math.random() * 10) + 1) >=4){
console.log("M1b gets req and passes it on to two")
next()
} else {
throw "ARRRRRRRRRRRRRGGGGHHHHHH!"
}
})
//some common treatment for all the above endpoints
app.use((req, resp, next) => {
response += " and M2"
if ( Math.floor((Math.random() * 10) + 1) >=4){
console.log("M2 gets req and passes it on to GET()")
next()
} else {
throw "ARRRRRRRRRRRRRGGGGHHHHHH!"
}
})
//get - need 1 get per endpoint?
app.get("/middlewaredemoa",(req,resp) => {
console.log("GET() handler after the middlewares")
resp.send(response + " and GET() 1")
})
app.get("/middlewaredemob",(req,resp) => {
console.log("GET() handler after the middlewares")
resp.send(response + " and GET() 2")
})
/*ERROR HANDLING - could use same pattern as above to chain errors*/
app.use((err, req, resp, next) => {
console.log("CRASH BOOM UH!:"+err)
resp.status(500).send("Poop hit the fan HARD")
})
答案 0 :(得分:1)
Express提供了一种使用数组来匹配多个路由的方法。
赞:
req.get(['/routea', '/routeb'], (req, res, next) => {
// do something
// res.send() if you want to send a response right away
// next() if you want to go to the next middleware
});
req.get
只是类似于req.use
的中间件,只匹配req.method === 'GET'
编辑:对于注释中的奖励问题。 它只是一个中间件。使用与普通中间件相同的缩放技术。