在PowerShell中使用Get-Acl时,如何显示属于组的所有成员而不是组本身?
所以:
Get-ChildItem C:\ | where-object {($_.PsIsContainer)} | Get-Acl | select path -ExpandProperty Access
显示如下内容:
Path : Microsoft.PowerShell.Core\FileSystem::C:\Test
FileSystemRights : FullControl
AccessControlType : Allow
IdentityReference : BUILTIN\Administrators
IsInherited : False
InheritanceFlags : ContainerInherit, ObjectInherit
PropagationFlags : None
Path : Microsoft.PowerShell.Core\FileSystem::C:\Test
FileSystemRights : ReadAndExecute, Synchronize
AccessControlType : Allow
IdentityReference : BUILTIN\Users
IsInherited : False
InheritanceFlags : ContainerInherit, ObjectInherit
PropagationFlags : None
相反,我希望它列出所有属于每个文件夹权限的Administrators / Users用户,并丢弃该组。
又如何将Convert-Path添加到select path语句中,以使显示的路径仅为C:\ Test?
谢谢!
答案 0 :(得分:0)
我无法通过链接发布和/或PowerShell Access Control模块来解决它,但仍然只有组。因此,最终我可以通过结合其他各种有用的帖子获得所需的信息,例如:
PowerShell script to return members of multiple security groups
List user details from Username
扩展我的原始问题,包括我想要的最终结果,这就是我的方法。它不是很漂亮(即使重复一小段代码),并且大部分可能会放在一行中,但是仅凭我自己的可读性,这种方式还是有意义的。另外,由于发现了有用的信息,我也省略了丢弃组的操作。
$queryPath = "C:\Test"
$targetFile = "C:\Test.csv"
$Table = @()
$Record = [ordered]@{
"Path" = ""
"IdentityReference" = ""
"Class" = ""
"GrpMember" = ""
}
$foldersToQuery = Get-ChildItem $queryPath | Where {$_.PSIsContainer} | select -expandproperty FullName
foreach ($folder in $foldersToQuery) {
$Record.Path = $folder
$permissions = Get-Acl $folder | select -expandproperty Access
foreach ($permission in $permissions) {
[string]$id = $permission.IdentityReference
$SamAccountName = $id.Split('\')[1]
$ADObject = Get-ADObject -Filter ('SamAccountName -eq "{0}"' -f $SamAccountName) }
$Record.IdentityReference = $permission.IdentityReference.ToString()
switch ($ADObject.ObjectClass) {
'user' {
$Record.Class = $ADObject.ObjectClass
$Record.GrpMember = ""
$objRecord = New-Object PSObject -property $Record
$Table += $objrecord
}
'group' {
$Record.Class = $ADObject.ObjectClass
$members = Get-ADGroupMember $SamAccountName }
foreach ($member in $members) {
$Record.GrpMember = $member.name
$objRecord = New-Object PSObject -property $Record
$Table += $objrecord
}
}
}
}
}
$Table | export-csv $targetFile -NoTypeInformation -Encoding UTF8