Question

当我尝试进行6/3的除法时，输出结果如下2 / -1431650288。代码有什么问题？我在c中的程序是这样的：

#include <stdio.h>

int main(){

    char Operator;
    int num1, num2;

    printf("Enter the operator in which you want to perform calculation(+, -, *, /)\n");
    scanf(" %c", &Operator);

    if (Operator == '/'){
        printf("Enter two numbers: ");
    scanf(" %d %d", &num1, &num2);
     if (num2==0){
            printf("\a Denominator must be greater than 0.\n");
        }
        else{
            printf(" %d / %d", num1/num2);
        }
    } 
    else{
    printf("Enter two integer numbers: ");
    scanf(" %d %d", &num1, &num2);

    if(Operator =='+'){
        printf(" %d + %d = %d", num1, num2, num1+num2);
    }
    else if(Operator == '-'){
      printf(" %d - %d = %d", num1, num2, num1-num2);
    }
    else if(Operator == '*'){
      printf(" %d * %d = %d", num1, num2, num1*num2);
    }

    else{
       printf("\t \a Invalid Operator.\n");
    }

    }
}

Answer 1

此行：

printf(" %d / %d", num1/num2);

第一个'％d'是num1 / num2的结果，这就足够了。第二个％d和'/'字符不应在此处。更改为：

printf(" %d ", num1/num2);

此外，出于您的目的，开关盒结构更适合代码可读性（我认为也是更好的优化）

为什么输出会这样？

1 个答案: