Question

我正在尝试使用ProductID创建一个有效的搜索字段，然后使用它在ProductID存在的产品表中显示该行。我遇到的问题是，如果我具有以下代码：以下提交按钮将执行$deleteprod和$deltesale代码，根据我的理解，所有代码应提交ProductID变量。

<form action="delete.php" method="post">
    <input value="" placeholder="Product ID" name="ProductID" type="text"/> <br>
    <input type="submit" onclick="" value="Search"/
</form>
<?php 

    $ProductID = $_POST['ProductID'];
    $db = mysql_connect("localhost:3307", "root", "usbw");
    $deleteprod = mysql_query("DELETE FROM gameshop.product WHERE (product.ProductID = '$ProductID')");
    $deletesale = mysql_query("DELETE FROM gameshop.sale WHERE (sale.ProductID = '$ProductID')");
    $deletebutton = "<button onclick=\"$deletesale; $deleteprod; location.href='database.php'\" style='width:200px; background-color:red;'>Delete Row</button>"; 
    mysql_select_db("gameshop",$db);
    $result = mysql_query("SELECT product.*, sale.Price
        FROM gameshop.product, gameshop.sale 
        WHERE (product.ProductID = '$ProductID' AND sale.ProductID = '$ProductID')",$db);
    if (!$result){
        print mysql_rror();
    }
    elseif ($myrow = mysql_fetch_array($result)){
        echo "<table style='text-align:center;' border=1>\n";
        echo "<tr><td>Product ID</td><td>Product Name</td>", "<td>Publisher</td><td>Developer</td>", "<td>Release Date</td><td>Stock</td>", "<td>Console</td>       <td>Rank</td><td>Price</td><td>Delete?</td></tr>\n";
        do{
            printf("<tr><td>%4d</td><td>%s</td><td>%s</td><td>%s</td><td>%s</td><td>%1d</td><td>%s</td><td>%1d</td><td>%2d</td><td>%s</td></tr>\n", // %s are syntax (string)
            $myrow["ProductID"], $myrow["ProductName"], $myrow["Publisher"], $myrow["Developer"], $myrow["ReleaseDate"], $myrow["Stock"], $myrow["Console"], $myrow["Rank"], $myrow["Price"], $deletebutton);
        }
        while ($myrow = mysql_fetch_array($result));
        echo "</table>\n";
    }
    mysql_close($db);
?>

如果我将$db = MySQL_connect("localhost:3307", "root", "usbw");移到$delete变量下面，则不会发生此问题，它会创建单行表。但是，当尝试单击$deletebutton时，该代码不会执行，并且不会删除任何行。我究竟做错了什么？

Answer 1

问题是，当您单击按钮时，您调用的是JavaScript，而不是PHP。
我认为您可以解决它，使用deletesale和deleteprod制作另一个PHP页面，而将Product_ID和post一起使用。
因此此文件将具有如下所示的php脚本：

$ProductID = $_POST['ProductID'];
$db = mysql_connect("localhost:3307", "root", "usbw");
mysql_select_db("gameshop",$db);
$result = mysql_query("SELECT product.*, sale.Price
    FROM gameshop.product, gameshop.sale 
    WHERE (product.ProductID = '$ProductID' AND sale.ProductID = '$ProductID')",$db);
if (!$result){
    print mysql_error();
}
elseif ($myrow = mysql_fetch_array($result)){
    echo "<table style='text-align:center;' border=1>\n";
    echo "<tr><td>Product ID</td><td>Product Name</td>", "<td>Publisher</td> <td>Developer</td>", "<td>Release Date</td><td>Stock</td>", "<td>Console</td>       <td>Rank</td><td>Price</td><td>Delete?</td></tr>\n";
    do{
        printf("<tr><td>%4d</td><td>%s</td><td>%s</td><td>%s</td><td>%s</td><td>%1d</td><td>%s</td><td>%1d</td><td>%2d</td><td>",$myrow["ProductID"], $myrow["ProductName"], $myrow["Publisher"], $myrow["Developer"], $myrow["ReleaseDate"], $myrow["Stock"], $myrow["Console"], $myrow["Rank"], $myrow["Price"]);
        printf "<form method=\"post\" action=\"delete_page.php\"><input type=\"text\" style=\"display:none\" name=\"ProductID\" value=\"$ProductID\"/><input type=\"submit\" value=\"delete product\"/></form>"
        printf "</td></tr>"
    }
    while ($myrow = mysql_fetch_array($result));
    echo "</table>\n";
}
mysql_close($db);

然后您将delete_page.php与

$ProductID = $_POST['ProductID'];
$db = mysql_connect("localhost:3307", "root", "usbw");
mysql_select_db("gameshop",$db);
mysql_query("DELETE FROM gameshop.product WHERE (product.ProductID = '$ProductID')");
mysql_query("DELETE FROM gameshop.sale WHERE (sale.ProductID = '$ProductID')");
mysql_close($db);

然后您可以将链接添加回到首页。

请确保检查拼写错误：）

声明变量运行变量

1 个答案: