Question

所以我成功读取了这样的CSV文件（该CSV文件有4列，分别带有x，y，u，v）-

while(4 == fscanf(fp, "%f %f %f %f\n", &d.xvalue, &d.yvalue, &d.uvalue, &d.vvalue))
{
    dataset = realloc(dataset, sizeof(*dataset) * (total + 1));
    dataset[total] = d;
    total++;
}

结构-

typedef struct {
    double xvalue;
    double yvalue;
    double uvalue;
    double vvalue;
} flow_data;

但是对于大型CSV文件，它执行了超过100,000次的重新分配。我已经尝试将其简化为类似这样的内容，但现在根本无法阅读。

// Reading flow_data.csv
FILE* fp = fopen(flow_file, "r");

// Checking if the file has been read succesfully
if( fp == NULL)
{
    perror("Error opening file");
    exit(1);
}

char buf[500];
fgets(buf, sizeof(buf), fp); // Skip the first line

int total = 0;
int buf_size = INITIAL_SIZE;
flow_data d;
flow_data* dataset = (flow_data*)malloc(sizeof(flow_data) * buf_size);

while(4 == fscanf(fp, "%lf, %lf, %lf, %lf\n", &d.xvalue, &d.yvalue, &d.uvalue, &d.vvalue))
{
    if (d.xvalue >= 0)
    {
    if (total >= buf_size) {
        buf_size = buf_size * 2;
        dataset = realloc(dataset,buf_size * sizeof(flow_data));
        if (dataset == NULL) {
            printf("error allocating memory!\n");
            exit(EXIT_FAILURE);
        }
    }
    dataset[total] = d;
    total++;
    }
}

仅当X值大于20时才读取该行。我在做什么错了？

Answer 1

以下是对d.xvalue >= 20条件进行测试的大小加倍代码的实现：

#include <stdio.h>
#include <stdlib.h>

typedef struct
{
    double xvalue;
    double yvalue;
    double uvalue;
    double vvalue;
} flow_data;

static void print_dataset(size_t size, flow_data dataset[size]);

int main(void)
{
    char flow_file[] = "flow_data.csv";
    FILE *fp = fopen(flow_file, "r");

    if (fp == NULL)
    {
        perror(flow_file);
        exit(1);
    }

    char buf[500];
    fgets(buf, sizeof(buf), fp); // Skip the first line

    size_t total = 0;
    size_t buf_size = 0;
    flow_data *dataset = NULL;

    flow_data d;
    while (4 == fscanf(fp, "%lf, %lf, %lf, %lf\n", &d.xvalue, &d.yvalue, &d.uvalue, &d.vvalue))
    {
        if (d.xvalue >= 20)
        {
            if (total >= buf_size)
            {
                size_t new_size = buf_size * 2 + 2;
                flow_data *new_data = realloc(dataset, new_size * sizeof(flow_data));
                if (new_data == NULL)
                {
                    printf("error allocating memory!\n");
                    free(dataset);
                    exit(EXIT_FAILURE);
                }
                dataset = new_data;
                buf_size = new_size;
            }
            dataset[total++] = d;
        }
    }

    /* Very unlikely to fail */
    dataset = realloc(dataset, total * sizeof(flow_data));

    print_dataset(total, dataset);

    free(dataset);
    fclose(fp);

    return 0;
}

static void print_dataset(size_t size, flow_data dataset[size])
{
    for (size_t i = 0; i < size; i++)
    {
        printf("[%zu]: (%f, %f) (%f, %f)\n", i,
               dataset[i].xvalue, dataset[i].yvalue,
               dataset[i].uvalue, dataset[i].vvalue);
    }
}

给出这样的示例数据文件（40行）：

22.3,22.3,25.3,24.8
26.5,25.3,21.5,11.5
17.5,12.6,12.8,17.6
17.2,28.5,17.0,23.7
29.6,29.1,28.5,14.2
20.1,15.5,21.5,16.4
26.9,29.0,25.6,13.1
16.7,29.0,26.7,16.4
22.8,14.7,17.4,12.5
27.2,13.8,26.6,25.0
26.7,13.1,26.2,19.3
20.8,25.3,28.8,10.6
27.0,27.0,16.7,10.4
18.4,23.3,16.9,25.9
27.7,17.3,29.2,26.8
14.2,27.6,16.2,10.1
21.7,11.4,21.2,12.6
20.6,12.4,25.5,15.5
29.0,11.4,12.1,18.1
25.7,22.3,24.4,12.9
10.6,22.1,25.6,18.7
25.5,25.1,25.0,29.7
27.3,11.4,16.1,11.3
14.7,11.1,24.0,15.1
29.7,12.1,11.1,22.5
10.5,13.7,22.6,22.6
25.1,16.3,21.2,13.8
17.1,11.5,12.0,24.6
17.5,24.1,19.3,24.8
12.5,29.8,19.7,10.6
11.2,19.6,17.8,24.5
22.4,12.9,10.3,25.8
17.7,10.1,27.9,21.4
18.5,11.7,16.5,24.5
17.0,26.0,20.2,29.6
20.1,11.8,22.3,20.7
25.1,14.1,25.3,13.5
22.6,14.1,26.4,16.2
13.0,29.2,14.7,19.6
17.3,12.6,28.2,15.1

它产生输出：

[0]: (26.500000, 25.300000) (21.500000, 11.500000)
[1]: (29.600000, 29.100000) (28.500000, 14.200000)
[2]: (20.100000, 15.500000) (21.500000, 16.400000)
[3]: (26.900000, 29.000000) (25.600000, 13.100000)
[4]: (22.800000, 14.700000) (17.400000, 12.500000)
[5]: (27.200000, 13.800000) (26.600000, 25.000000)
[6]: (26.700000, 13.100000) (26.200000, 19.300000)
[7]: (20.800000, 25.300000) (28.800000, 10.600000)
[8]: (27.000000, 27.000000) (16.700000, 10.400000)
[9]: (27.700000, 17.300000) (29.200000, 26.800000)
[10]: (21.700000, 11.400000) (21.200000, 12.600000)
[11]: (20.600000, 12.400000) (25.500000, 15.500000)
[12]: (29.000000, 11.400000) (12.100000, 18.100000)
[13]: (25.700000, 22.300000) (24.400000, 12.900000)
[14]: (25.500000, 25.100000) (25.000000, 29.700000)
[15]: (27.300000, 11.400000) (16.100000, 11.300000)
[16]: (29.700000, 12.100000) (11.100000, 22.500000)
[17]: (25.100000, 16.300000) (21.200000, 13.800000)
[18]: (22.400000, 12.900000) (10.300000, 25.800000)
[19]: (20.100000, 11.800000) (22.300000, 20.700000)
[20]: (25.100000, 14.100000) (25.300000, 13.500000)
[21]: (22.600000, 14.100000) (26.400000, 16.200000)

在运行带有GCC 8.2.0和Valgrind 3.14.0.GIT的macOS 10.13.6 High Sierra的Mac上进行测试时，它可以在Valgrind下正常运行（由Git存储库的副本构建的Valgrind版本）而不是正式版本。

==76412== HEAP SUMMARY:
==76412==     in use at exit: 23,135 bytes in 168 blocks
==76412==   total heap usage: 195 allocs, 27 frees, 99,487 bytes allocated
==76412== 
==76412== LEAK SUMMARY:
==76412==    definitely lost: 0 bytes in 0 blocks
==76412==    indirectly lost: 0 bytes in 0 blocks
==76412==      possibly lost: 0 bytes in 0 blocks
==76412==    still reachable: 0 bytes in 0 blocks
==76412==         suppressed: 23,135 bytes in 168 blocks

读取CSV文件-内存问题

1 个答案: