在for循环打字稿和nhibernate死锁中调用异步函数

时间:2018-09-02 15:01:34

标签: c# angularjs typescript asp.net-web-api nhibernate

我正在用打字稿在for循环内编写一个http post调用。

在后端调试方法时,我注意到他同时处理了请求。

例如,假设服务器必须为每个单个请求运行2个方法M1(),然后运行M2()。对于n = 2的测试用例,服务器对请求1执行M1(),对请求2执行M1(),然后对请求2执行M2(),最后对请求2执行M2()

然后在_session.commit()之后,在方法拦截器中引发异常。异常描述为:

  

NHibernate.StaleObjectStateException:'行已由另一个事务更新或删除(或未保存的值映射不正确):[Server.Model.Identity.ApplicationRole#3]'

代码:

public calculate(index?: number): void {
    for (var i = 0; i < this.policy.coverages.length; i++) {
        this.callCalculate(i);
    }
}

public callCalculate(i: number): void {
    this.premiumCalculationParams = this.policy.createPremiumCalculationParams();

    if (!this.premiums) {
        this.premiums = new Array(this.policy.coverages.length);
    }

    this.offerService.calculatePremiums(this.policy, i).then((result: any) => {

        this.premiums[i] = new Array<Premium>();
        this.surpremiums = new Array<PremiumResult>();

        if (result.data && result.data.premiumTable && result.data.premiumTable.premiumPayment && result.data.premiumTable.premiumPayment.premiums && result.data.premiumTable.premiumPayment.premiums.length > 0) {
            _.each(result.data.premiumTable.premiumPayment.premiums, (premiumValue: any) => {
                let premium: Premium = new Premium();
                premium.setPremium(premiumValue);
                this.premiums[i].push(premium);
                this.policy.getCoverage(i).premiumPayment.premiums = angular.copy(this.premiums[i]);
            });

            if (result.data && result.data.results && result.data.results.length > 0) {
                _.each(result.data.results, (premiumValuel: any) => {
                    let sp = new PremiumResult();
                    sp.setPremiumResult(premiumValuel);
                    sp.premiums = new Array<Premium>();
                    _.each(premiumValuel.premiums, (premiumValue: any) => {
                        let premium: Premium = new Premium();
                        premium.setPremium(premiumValue);
                        sp.premiums.push(premium);
                    });
                    this.surpremiums.push(sp);
                });
            }

            console.log(this.surpremiums);
        }

        if (result.data && result.data.premiumTable && result.data.premiumTable.messageList && result.data.premiumTable.messageList.messages && result.data.premiumTable.messageList.messages.length > 0) {
            _.each(result.data.premiumTable.messageList.messages, (message: any) => {
                let messageType: any = MessageType[message.messageLevel.toString()];
                this.messages.push(new Message(messageType, "premiums", message.messageContent, this.premiums[i]));
            });

        }

    }, (err: any) => {
        this.premiums[i] = null;
        this.surpremiums = null;
        if (err && err.data && err.data.modelState) {
            for (var key in err.data.modelState) {
                var model = err.data.modelState[key];
                _.each(model, (state: string) => {
                    this.$log.debug(OfferControllerPrefix, "Calculation failed: " + state);
                });
            }
        }

        this.messages.push(new Message(MessageType.SVR_ERROR, "premiumCalculationParams", this.jsTranslations.getTranslation(Constants.DEFAULT_ERROR_NL), this.policy));
    });

}
public calculatePremiums(policy: Policy, selectedCoverageIndex : number): any {
    var uri = this.uriService.buildURI("Policy/Calculate");
    var data = {
        'policy': policy,
        'selectedCoverageIndex': selectedCoverageIndex
    };
    return this.$http.post<any>(uri, data);
}

如何解决此问题?

1 个答案:

答案 0 :(得分:0)

要链接两个异步操作,请将值返回到它们的.then方法:

function M1(data) {
    return $http.post(url1, data);
}

function M2(data) {
    return $http.post(url2, data);
}

像这样束缚两个功能:

function M1M2 () {

    var promise = M1(data);

    var promise2 = promise.then(function(data) {
       var data2 = fn(data);
       var m2Promise = M2(data2);
       return m2Promise;
    });

    return promise2;
}

由于调用promise的.then方法会返回新的派生promise,因此很容易创建promise的promise。

可以创建任意长度的链,并且由于一个承诺可以用另一个承诺来解决(这将进一步推迟其解决方案),因此可以在链中的任何点暂停/推迟对承诺的解决。这样就可以实现功能强大的API。

有关更多信息,请参见AngularJS $q Service API Reference - chaining promises

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