在以下程序中，我试图在pyqt5中创建一个计算器。连接计算器按钮的信号时遇到麻烦。
class Calci(QWidget):
def __init__(self, Parent=None):
super(Calci,self).__init__()
self.initgui()
def initgui(self):
list1= ["%","rt","pow","1/x","CE","C","BCK",
"/","7","8","9","*","4","5","6","-",
"1","2","3","+","+-","0",".","="]
list2=[(i,j) for i in range(2,8) for j in range(0,4)]
self.button={}
self.lineedit=QLineEdit()
self.lineedit.setFocus()
grid=QGridLayout()
self.setLayout(grid)
self.font=QFont("Bookman Old Style",15,25)
self.lineedit.setFont(self.font)
for x,y in zip(list1,list2):
self.button[y]=QPushButton(x)
grid.addWidget(self.lineedit,0,0,2,4)
self.lineedit.setSizePolicy(QSizePolicy.Preferred,
QSizePolicy.Expanding)
self.lineedit.setMinimumHeight(70)
grid.addWidget(self.button[y],*y)
self.button[y].setSizePolicy(QSizePolicy.Preferred,
QSizePolicy.Expanding)
self.button[y].setMinimumHeight(70)
self.lineedit.setAlignment(Qt.AlignRight)
self.button[y].clicked.connect(lambda: self.click(x))
def click(self,n):
self.lineedit.insert(n)
app=QApplication(sys.argv)
calci=Calci()
calci.show()
app.exec_()
我正在使用以下行self.button [y] .clicked.connect（lambda：self.click（x）） 反映按到Qlineedit上的按钮，但问题是我按的那个按钮仅给出“ =”，这是list1中的最后一项。我认为循环中没有问题，因为所有按钮在被按下时都给出响应，但是它们都给出相同的响应。
我的问题是：所有按钮都已连接，就像每当我按下一个按钮时，它都会给出响应，但没有给出正确的响应。我应该对代码进行哪些更改才能获得正确的代码响应。还有其他方法可以尝试连接信号吗？
