我提交模型时将其设置为null

Question

我正在尝试更新表中的记录，但是当我提交记录时，将其设置为Null。

我想发生的事情是拥有一个多表单视图页面，我可以在其中编辑我的ParentModel 以及我模型中的记录

我有一个适用于Parentmodel的提交按钮 并为Model1s中的每个Recod提供一个提交按钮

但是每次我提交任何model1s记录时，调试都会说我的模型为空

我对ASP.Net相当陌生，并且已经从该论坛中进行了大量搜索， 我希望你能帮助我

欢呼

查看模型

using System;
using System.Collections.Generic;
using System.ComponentModel.DataAnnotations;
using System.ComponentModel.DataAnnotations.Schema;
using System.Linq;
using System.Web;

namespace WebApplication1.Models
{

    public class CombineModel
    {
        public ParentModel ParentModel { get; set; }
        public IEnumerable<Model1> Model1s { get; set; }
    }


}

控制器

using System;
using System.Collections.Generic;
using System.Data;
using System.Data.Entity;
using System.Linq;
using System.Net;
using System.Web;
using System.Web.Mvc;
using WebApplication1.Models;

namespace WebApplication1.Controllers
{
    public class CombineModelController : Controller
    {
        private ApplicationDbContext db = new ApplicationDbContext();


        public ActionResult Details(string id)
        {
            if (id == null)
            {
                return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
            }

            CombineModel CombineModel = new CombineModel();

            CombineModel.ParentModel = db.ParentModel.Find(id);
            CombineModel.Model1s = db.Model1.Where(x => x.ParentId.Equals(id));

            if (CombineModel == null)
            {
                return HttpNotFound();
            }
            return View(CombineModel);

        }

        [HttpPost]
        [ValidateAntiForgeryToken]
        public ActionResult Details(CombineModel model)
        {
            if (ModelState.IsValid)
            {
                db.Entry(model.ParentModel).State = EntityState.Modified;
                db.SaveChanges();
            }

            CombineModel CombineModel = new CombineModel();

            CombineModel.ParentModel = db.ParentModel.Find(model.ParentModel.ParentId);
            CombineModel.Model1s = db.Model1.Where(x => x.ParentId.Equals(model.ParentModel.ParentId));

            if (CombineModel == null)
            {
                return HttpNotFound();
            }
            return View(CombineModel);
        }




               [HttpPost]
        [ValidateAntiForgeryToken]
        public ActionResult EditChild([Bind(Prefix = "Model1")] Model1 model)
        {
            db.Entry(model).State = EntityState.Modified;
            db.SaveChanges();
            return RedirectToAction("Details", "CombineModel", new { id = model.ParentId });
        }




    }
}

查看

@model WebApplication1.Models.CombineModel

@{
    ViewBag.Title = "Details";
}

@using (Html.BeginForm())
{
    @Html.AntiForgeryToken()

    <div class="form-horizontal">
        <h4>Combine Model</h4>
        <hr />
        @Html.HiddenFor(model => model.ParentModel.ParentId)

        <div class="form-group">
            @Html.LabelFor(model => model.ParentModel.Name, htmlAttributes: new { @class = "control-label col-md-2" })
            <div class="col-md-10">
                @Html.EditorFor(model => model.ParentModel.Name, new { htmlAttributes = new { @class = "form-control" } })
            </div>
        </div>

        <div class="form-group">
            <div class="col-md-offset-2 col-md-10">
                <input type="submit" value="Save" class="btn btn-default" />
            </div>
        </div>
    </div>
}

    <table class="table">
        <tr>
            <th>
                Name
            </th>

        </tr>

        
        @foreach (var item in Model.Model1s)
        {
            <tr>
                <td>
                    @using (Html.BeginForm("EditChild", "CombineModel", FormMethod.Post, new { }))
                    {
                        @Html.AntiForgeryToken()

                        @Html.EditorFor(modelItem => item.Id)
                        @Html.EditorFor(modelItem => item.ParentId)
                        @Html.EditorFor(modelItem => item.Name)

                        <div class="form-group">
                            <div class="col-md-offset-2 col-md-10">
                                <input type="submit" value="Save-2" class="btn btn-default" />
                            </div>
                        </div>
                    }
                </td>

            </tr>
        }




    </table>






@section Scripts {
    @Scripts.Render("~/bundles/jqueryval")
}