Question

So I'm currently making a site that includes purchases. Instead of signing up I want to set a cookie then every time a user clicks the buy button, it'll add 1 to the cookie name. Then when the cookie name = $_POST['user'] + 10 I want to echo 'too many right now' or something along those lines. I can't get this to work and have tried multiple times. There is no error in my html or anywhere else in my html. I just can't get this to work. Here is my code:

<?php  
$cookie_name = $_POST['user'];
setcookie($cookie_name,  time() + (86400 * 30), "/");

if(!isset($_COOKIE[$cookie_name])) {
print 'Cookie with name "' . $cookie_name . '" does not exist...';
} else {
print'Cookie with name "'. $cookie_name .'"value is:'.$_COOKIE[$cookie_name];
}
if(isset($_POST['button'])) {
setcookie($cookie_name, '+1', $cookie_value);

}

if (setcookie($cookie_name == $_POST['user'], +10)) {
echo 'to many right now';
}
?>

I obviously have a html form with the attributes name = 'button' and name = 'user' I just want to know how I can achieve what I said I was trying to do above. Any help is appreciated, thanks.

Answer 1

您显然已经超出了深度，并希望setcookie将以某种方式为您完成所有工作，阅读，调整和测试Cookie。作为the manual makes clear，它只做一件事：

setcookie（）定义要与其余HTTP标头一起发送的cookie。

它有两个主要参数：一个字符串，它是要发送到浏览器的cookie的名称；一个字符串，它是要发送的值；其他参数都是可选的，并更改何时何地可见；现在暂时忽略它们。请注意，第二个参数不是方程式，也不是要进行的调整，它只是要存储的文本字符串。

和以往一样，关键是分解问题；完成以下每个步骤，并确保其正常工作，然后再进行下一步：

确定cookie的名称（不会更改的部分，因为稍后您会再次找到它）。
测试是否已在上一个请求中设置了cookie。
如果有，请将其值放入新变量中。
将该值增加1
如果没有现有的cookie，请将变量设置为初始值，例如0或1
使用setcookie
测试该值是否已达到某个阈值，并回显一条消息。

请注意，在上文中，只有一个呼叫setcookie；您的大多数逻辑只是处理数字，而根本不需要了解Cookie。

set cookie add 1 to cookie name everytime user clicks button

1 个答案: