Question

我正在与Team View QuickSupport类似的项目中工作，我想知道AccessibilityService是否允许在可以提取保护设备密码的远程屏幕上执行滑动操作？

我尝试以下代码，但没有成功。到目前为止，所有发生的事情都是android代码中的一个异常：

java.lang.IllegalStateException：尝试向手势添加太多笔触

此处：

gestureBuilder.addStroke(new GestureDescription.StrokeDescription(path, 0, time));

当前的Java代码是这样的：

    if (xline.contains("mouseswipescreen")) {

     String coords = xline.replace("mouseswipescreen", "");

     String[] tokens = coords.split(Pattern.quote("<|>"));

               float x = parseFloat(tokens[0]);
               float y = parseFloat(tokens[1]);
               String cmd = tokens[2];

     MyAccessibility.instance.Swipte((int) x, (int) y, 50, cmd);
 }

GestureDescription.Builder gestureBuilder;
Path path;

public void Swipte(int x, int y, int time, String command) {

    if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.N) {
        System.out.println(" ======= Swipte =======");

        if (command.equalsIgnoreCase("start")) {

            gestureBuilder = new GestureDescription.Builder();
            path = new Path();

            path.moveTo(x, y);

        } else if (command.equalsIgnoreCase("move")) {

            path.lineTo(x, y);
            gestureBuilder.addStroke(new GestureDescription.StrokeDescription(path, 0, time));

        } else if (command.equalsIgnoreCase("dispatch")) {

            dispatchGesture(gestureBuilder.build(), new GestureResultCallback() {
                @Override
                public void onCompleted(GestureDescription gestureDescription) {
                    System.out.println("SWIPTE Gesture Completed :D");
                    super.onCompleted(gestureDescription);
                }
            }, null);
        }
    }

}

现在更改此代码以执行保持此状态的滑动屏幕：

public void Swipte(int x1, int y1, int x2, int y2, int time){

        if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.N) {

            System.out.println(" ======= Swipte =======");

            GestureDescription.Builder gestureBuilder = new GestureDescription.Builder();
            Path path = new Path();
            path.moveTo(x1,y1); // "mousedown"
            path.lineTo(x2,y2); // until last position found in "mousemove"

            gestureBuilder.addStroke(new GestureDescription.StrokeDescription(path, 0, time));
            dispatchGesture(gestureBuilder.build(), new GestureResultCallback() {
                @Override
                public void onCompleted(GestureDescription gestureDescription) {
                    System.out.println("SWIPTE Gesture Completed :D");
                    super.onCompleted(gestureDescription);
                }
            }, null);
        }

    }

结果是这样的：

看到密码错误。

最后根据上面第一个Java代码发送代码（reference）的代码（Delphi）：

 private
    { Private declarations }
    fDown: Boolean;
    fPO: TPoint;
  public
    { Public declarations }
  end;

  ...

procedure TForm2.Image1MouseDown(Sender: TObject; Button: TMouseButton;
  Shift: TShiftState; X, Y: Integer);
var
  Index, XTouch, YTouch, RXCoord, RYCoord: Integer;
  List: TStrings;
  RScreen, Start: String;
begin
  Index := Form1.ListView1.ItemIndex;
  if Index = -1 then
    Exit;

    List := TStringList.Create;
    RScreen := Form1.ListView1.Selected.SubItems[6]; // Remote screen resolution

    try
      ExtractStrings(['x'], [], PChar(RScreen), List); // Ex: my smartphone is 1920x1080
      RYCoord := StrToInt(List[0]);                    // 1920 (height)
      RXCoord := StrToInt(List[1]);                    // 1080 (width)
    finally
      List.Free;
    end;

    XTouch := Round((X / Image1.Width) * RXCoord);
    YTouch := Round((Y / Image1.Height) * RYCoord);

    fPO := Point(XTouch, YTouch);
    Start := 'start';
    fDown := true;

    Form1.ServerSocket1.Socket.Connections[Index].SendText(format('mouseswipescreen%d<|>%d<|>%s'#13#10, [fPO.X, fPO.Y, Start]));

  end;
end;

procedure TForm2.Image1MouseMove(Sender: TObject; Shift: TShiftState;
  X, Y: Integer);
var
  Index, XTouch, YTouch, RXCoord, RYCoord: Integer;
  List: TStrings;
  RScreen, Move: String;
begin

  Index := Form1.ListView1.ItemIndex;
  if Index = -1 then
    Exit;

  List := TStringList.Create;
  RScreen := Form1.ListView1.Selected.SubItems[6]; // Remote screen resolution

  try
    ExtractStrings(['x'], [], PChar(RScreen), List); // Ex: my smartphone is 1920x1080
    RYCoord := StrToInt(List[0]);                    // 1920 (height)
    RXCoord := StrToInt(List[1]);                    // 1080 (width)
  finally
    List.Free;
  end;

  XTouch := Round((X / Image1.Width) * RXCoord);
  YTouch := Round((Y / Image1.Height) * RYCoord);

  if fDown then
  begin

    Move := 'move';

    Form1.ServerSocket1.Socket.Connections[Index].SendText(format('mouseswipescreen%d<|>%d<|>%s'#13#10, [fPO.X, fPO.Y, Move]));

    fPO := Point(XTouch, YTouch);

  end;

end;

procedure TForm2.Image1MouseUp(Sender: TObject; Button: TMouseButton;
  Shift: TShiftState; X, Y: Integer);
begin
  if fDown then
    fDown := false;
end;

Answer 1

好的，我已经回答了我自己的问题，AccessibilityService的专家已经认为我正在构建恶意软件，而不喜欢帮助这类人。

答案：

不幸的是，我的上述方法是正确的，直到这一刻为止，由于存在limitation on storage of gestures，here是官方参考，所以无法使用AccessibilityService来实现此目标

addStroke(new GestureDescription.StrokeDescription(path, 0, time));

而且，到目前为止（在这种情况下）AccessibilityService在某点（由9个组成的点）中无法执行触摸手势“ 仅按下而不松动”密码屏幕），然后执行两次快速鼠标单击并发送：

procedure TForm2.Image1MouseDown(Sender: TObject; Button: TMouseButton;
  Shift: TShiftState; X, Y: Integer);

在开始输入密码之前和输入密码期间（拖动鼠标），只有在完全输入密码后才释放密码：

procedure TForm2.Image1MouseUp(Sender: TObject; Button: TMouseButton;
  Shift: TShiftState; X, Y: Integer);

被发送到远程设备。

编辑：

注意： Team View QuickSupport之所以能够做到这一点，是因为使用了code of root gave to he by several vendors。

AccessibilityService：可以使用鼠标在远程智能手机屏幕上绘制密码吗？

1 个答案: