Question

我有这个SQL查询，可以返回整个集合：

SELECT s.id, s.status, s.created_at
FROM scores s
WHERE s.account_id IN (
  SELECT a.id
  FROM accounts a
  WHERE a.status = 'ACTIVE' AND a.created_at >= DATE(NOW()) - 3 AND a.tool = 'GLR'
) ORDER BY s.created_at ASC;

...但是现在我想要一个子集：account中的所有记录在score中没有任何记录。

我已经尝试过这些，但是到目前为止还没有运气O：）

--- Using LEFT JOIN
SELECT s.account_id, s.status, s.created_at
FROM scores s
  LEFT JOIN accounts a ON s.account_id = a.id
    AND a.status = 'ACTIVE'
    AND a.created_at >= DATE(NOW()) - 3
    AND a.tool = 'GLR'
WHERE s.account_id IS NULL ORDER BY s.created_at ASC;

--- Using EXISTS / NOT EXISTS
SELECT s.account_id, s.status, s.created_at
FROM scores s
WHERE NOT EXISTS (
  SELECT 1 FROM accounts a
  WHERE s.account_id = a.id
    AND a.status = 'ACTIVE'
    AND a.created_at >= DATE(NOW()) - 3
    AND a.tool = 'GLR'
) ORDER BY s.created_at ASC;

Answer 1

SELECT a.* FROM accounts a LEFT JOIN scores s ON s.account_id = a.id
WHERE a.status = 'ACTIVE' AND a.created_at >= DATE(NOW()) - 3 AND a.tool = 'GLR'
  AND s.account_id IS NULL

返回其他表中不存在的记录子集

1 个答案: