Question

我遇到的问题是当电子邮件发送给我时，发送到我的电子邮件的结果在html表中的格式不正确。

首先，这是我的查询。第一个查询将使用包含类型M和C的数据构建一个临时表。第二个查询将构建另一个临时表并比较之前创建的临时表，并检查数据是否包含M或C类型。

use Letters

-- Build a temp table with the M and C Denial letters. We do not want to include these in our final list.

select distinct
LT.Description
into #ModCarvLetters
from dbo.AELetters_LetterTemplateText TT (nolock)
inner join dbo.AELetters_LetterTemplates LT (nolock) on 
TT.TemplateUniqueID = LT.TemplateUniqueID
inner join dbo.AELetters_LetterAssignment LA (nolock) on
LT.TemplateUniqueID = LA.TemplateUniqueID
inner join dbo.AELetters_LetterAssignmentDetail LAD (nolock) on
LA.LetterAssignmentID = LAD.LetterAssignmentID
where CurrentVersion = 1
and LT.TemplateType = 'Auto'
and LAD.LetterAssignment_lkupID = 3 --- Autst
and (LAD.MatchTableColumnValue =  'C' or LAD.MatchTableColumnValue =  'M')
and cast(LA.EffFrom as DATE) <= cast(GETDATE() as DATE)
and cast(LA.EffTo as DATE) >= cast(GETDATE() as DATE)
order by LT.Description

-- Get the language from the letter just before the denial reason.

select distinct
LT.Description,
substring(TT.TemplateText, charindex('Denial', TT.TemplateText)-500, 500) as [Denial_Reason]
into #DenialLetters
from dbo.AELetters_LetterTemplateText TT (nolock)
inner join dbo.AELetters_LetterTemplates LT (nolock) on 
TT.TemplateUniqueID = LT.TemplateUniqueID
inner join dbo.AELetters_LetterAssignment LA (nolock) on
LT.TemplateUniqueID = LA.TemplateUniqueID
inner join dbo.AELetters_LetterAssignmentDetail LAD (nolock) on
LA.LetterAssignmentID = LAD.LetterAssignmentID
where CurrentVersion = 1
and LT.TemplateType = 'Auto'
and TT.LanguageCodeID  = 65 -- English
--and LAD.LetterAssignment_lkupID = 2
and LAD.MatchTableColumnValue = 'Denied'
and cast(LA.EffFrom as DATE) <= cast(GETDATE() as DATE)
and cast(LA.EffTo as DATE) >= cast(GETDATE() as DATE)
and LT.Description not in (select M.Description from  #ModCarvLetters M)
order by LT.Description desc--, TT.TemplateText

drop  table #ModCarvLetters

以下是我向结果发送电子邮件的地方。

DECLARE @CT AS INT
DECLARE @LETTER_DESCRIPTION AS VARCHAR (255)
DECLARE @DENIAL_REASON AS VARCHAR (MAX)
DECLARE @EMESSAGE AS VARCHAR (MAX)

SELECT @CT = COUNT(*) FROM  #DenialLetters

                        SET @EMESSAGE = '<head><style type="text/css">h2 {font-family: Arial, verdana;} td{background-color:#F1F1F1; border:1px solid black; padding:3px;} th{background-color:#99CCFF;}</style>
                        <h2><font color="#0000ff" size="4">DENIAL LETTERS ON TEST</font></h2></head><table border="1"><tr><th>Letter Description</th><th>Denial Reason</th></tr>';
                        --<h2><font color="#0000ff" size="4">DENIAL LETTERS ON PRODUCTION</font></h2></head><table border="1">' + '<tr><th>Letter Description</th><th>Denial Reason</th></tr>';

                        WHILE @CT > 0

                        BEGIN

                              SELECT @LETTER_DESCRIPTION = Description, @DENIAL_REASON = Denial_Reason  FROM  #DenialLetters

                              SET @EMESSAGE = @EMESSAGE + 
                              '<tr><td>' + @LETTER_DESCRIPTION + '</td><td>' +  @DENIAL_REASON + '</td></tr>' ;

                              DELETE FROM  #DenialLetters WHERE (Description = @LETTER_DESCRIPTION and Denial_Reason = @DENIAL_REASON)

                              SELECT @CT = COUNT(*) FROM  #DenialLetters
                              --Print @CT
                              --Print @LETTER_DESCRIPTION
                              --Print  @DENIAL_REASON
                        END

                        SET @EMESSAGE = @EMESSAGE + '</table>'

                        exec msdb.dbo.sp_send_dbmail      
                             @recipients = 'mbruhn@regalmed.com',
                             @subject = 'Denial letters on REA Test',
                           --@subject = 'Denial letters on REA Production',  
                             @body = @EMESSAGE,
                             @body_format = 'HTML'              

Drop table  #DenialLetters

这是我收到电子邮件时显示的结果。我遇到的问题是表格外的文本应在表格中。不应出现“！=”“）{％>”。

Answer 1

您可以尝试以下操作，而不是使用循环：

SET @EMESSAGE = @EMESSAGE + 
    (SELECT Description td, Denial_Reason td
     FROM #DenialLetters
     FOR XML RAW ('tr'), ELEMENTS)

发送的电子邮件格式不正确

1 个答案: