编辑：

Question

我是python / pygame的新手，对此我一无所知。每当我按住一个键时，它都不会循环KEYDOWN。另外，如果我按住键盘上的键并同时移动鼠标，它似乎会连续移动。

有人可以告诉我我在做什么错吗？

import pygame
import random
pygame.init()

#Colors
white = 255, 255, 255
black = 0, 0, 0
back_color = 48, 255, 124
light_color = 34, 155, 78

#Display W/H
display_width = 800
display_height = 600

#X/Y
x_axis = 400
y_axis = 580

Block_size = 20
x_int = 0
y_int = 0

ON = True



Window = pygame.display.set_mode((display_width, display_height))
pygame.display.set_caption('Game')



#On Loop
while ON == True:
    #Screen Event
    for Screen in pygame.event.get():
        #Quit Screen
        if Screen.type == pygame.QUIT:
            pygame.quit()
            exit()
        #Quit Full Screen
        if Screen.type == pygame.KEYDOWN:
            if Screen.key == pygame.K_q:
                pygame.quit()
                exit()

        #Full Screen !!!!!!!! EDIT THIS !!!!!!!!
        if Screen.type == pygame.KEYDOWN:
            if Screen.key == pygame.K_1:
                pygame.display.set_mode((display_width, display_height),pygame.FULLSCREEN)
            if Screen.key == pygame.K_2:
                pygame.display.set_mode((display_width, display_height))

        #Player Movement K DOWN
        if Screen.type == pygame.KEYDOWN:
            if Screen.key == pygame.K_d:
                x_int = 20
            if Screen.key == pygame.K_a:
                x_int = -20
       #Player Movement K UP
        if Screen.type == pygame.KEYUP:
            if Screen.key == pygame.K_d or Screen.key == pygame.K_a:
                x_int = 0

        x_axis += x_int



        Window.fill((back_color))
        Player = pygame.draw.rect(Window, light_color, [x_axis, y_axis, Block_size, Block_size])



        pygame.display.update()
quit()

Answer 1

我改进了您的代码。您已将屏幕更新（绘制屏幕）部分放置在事件循环中，而它应该在while循环中。我的模式代码有点复杂，但是可以正常工作。为什么它很复杂？按住键时，事件列表为空（您可以打印事件）。我还设置了阻止不退出屏幕的功能。块的速度很高，因此我将其降低为10。

import pygame
import random
pygame.init()

#Colors
white = 255, 255, 255
black = 0, 0, 0
back_color = 48, 255, 124
light_color = 34, 155, 78

#Display W/H
display_width = 800
display_height = 600

#X/Y
x_axis = 400
y_axis = 580
global x_int
Block_size = 20
x_int = 0
y_int = 0

ON = True



Window = pygame.display.set_mode((display_width, display_height))
pygame.display.set_caption('Game')

global topass_a,topass_d
x_int,topass_a,topass_d = 0,0,0
#On Loop
while ON:
    #Screen Event
    events = pygame.event.get()
    def on_a_press():
        global topass_a,x_int
        x_int = -10
        topass_a = 1
    def on_d_press():
        global topass_d,x_int
        x_int = 10
        topass_d = 1
    if len(events) == 0:
         if topass_a == 1:on_a_press()
         if topass_d == 1:on_d_press()
    for Screen in events:
        if Screen.type == pygame.QUIT:
            pygame.quit()
            exit()
        if Screen.type == pygame.KEYDOWN:
            if Screen.key == pygame.K_q:
                pygame.quit()
                exit()
            if Screen.key == pygame.K_1:
                    pygame.display.set_mode((display_width, display_height),pygame.FULLSCREEN)
            if Screen.key == pygame.K_2:
                    pygame.display.set_mode((display_width, display_height))
            if Screen.key == pygame.K_d or topass_d == 1:
                on_d_press()
            if Screen.key == pygame.K_a or topass_a == 1:
                on_a_press()
        if Screen.type == pygame.KEYUP:
            if Screen.key == pygame.K_d or Screen.key == pygame.K_a:
                x_int = 0
                topass_a = 0
                topass_d = 0

    x_axis += x_int
    x_int = 0
    if x_axis < 0:x_axis=0
    elif x_axis >= display_width-Block_size:x_axis = display_width-Block_size
    Window.fill((back_color))
    Player = pygame.draw.rect(Window, light_color, [x_axis, y_axis, Block_size, Block_size])
    pygame.display.update()

您可以根据需要进一步改进代码。

编辑：

为什么复杂？简单的事情首先出现。我已经意识到，无需跟踪按键。 pygame.key.get_pressed()返回按下的键。这是一个较小，更好和改进的代码。我还实现了w和s（y_axis）键。

import pygame
import random
pygame.init()

#Colors
white = 255, 255, 255
black = 0, 0, 0
back_color = 48, 255, 124
light_color = 34, 155, 78

#Display W/H
display_width = 800
display_height = 600

#X/Y
x_axis = 400
y_axis = 580
Block_size = 20
x_int = 0
y_int = 0

ON = True



Window = pygame.display.set_mode((display_width, display_height))
pygame.display.set_caption('Game')
while ON:
    events = pygame.event.get()
    for Screen in events:
        if Screen.type == pygame.QUIT:
            pygame.quit()
            exit()
        if Screen.type == pygame.KEYDOWN:
            if Screen.key == pygame.K_q:
                pygame.quit()
                exit()
            if Screen.key == pygame.K_1:
                    pygame.display.set_mode((display_width, display_height),pygame.FULLSCREEN)
            if Screen.key == pygame.K_2:
                    pygame.display.set_mode((display_width, display_height))

    keys = pygame.key.get_pressed()
    if keys[pygame.K_a]:
        x_int = -10
    if keys[pygame.K_d]:
        x_int = 10
    # keys controlling y axis, you can remove these lines
    if keys[pygame.K_w]:
        y_int = -10
    if keys[pygame.K_s]:
        y_int = 10
    #x_axis......
    x_axis += x_int
    x_int = 0
    if x_axis < 0:x_axis=0
    elif x_axis >= display_width-Block_size:x_axis = display_width-Block_size
    #y axis
    y_axis += y_int
    y_int = 0
    if y_axis < 0:y_axis=0
    elif y_axis >= display_height-Block_size:y_axis = display_height-Block_size
    #updaing screen
    Window.fill((back_color))
    Player = pygame.draw.rect(Window, light_color, [x_axis, y_axis, Block_size, Block_size])
    pygame.display.update()

Answer 2

仅在第一次按下键时才收到pygame.KEYDOWN，而在按住该键时不会收到。一种简单的解决方案是仅在按键按下时（即x_int != 0时）绘制

#On Loop
while ON == True:
    #Screen Event
    for Screen in pygame.event.get():
        # <Removed not relevant code for brevity>
        #Player Movement K DOWN
        if Screen.type == pygame.KEYDOWN:
            if Screen.key == pygame.K_d:
                x_int = 20
            if Screen.key == pygame.K_a:
                x_int = -20
       #Player Movement K UP
        if Screen.type == pygame.KEYUP:
            if Screen.key == pygame.K_d or Screen.key == pygame.K_a:
                x_int = 0

    # Render only happens if x_int is not zero
    # (Need to add code to force render first time)
    if x_int:
        x_axis += x_int
        Window.fill((back_color))
        Player = pygame.draw.rect(Window, light_color, [x_axis, y_axis, Block_size, Block_size])
        pygame.display.update()

随着程序的增长和变得越来越复杂，您将需要更好的逻辑以进行渲染，但这将使您入门。

如何在pygame中连续循环KEYDOWN？

2 个答案:

编辑：