我想在MySQL 8.0中获得查询的执行计划,但这给了我一个不完整计划。
于2018年9月8日编辑:
为了简化示例,原始查询最终以不检索任何行的子查询结束。似乎MySQL的优化程序将这些查询简化到完全修剪查询部分的程度。我修改了查询以获取有关子查询的数据。这是示例:
create table branch (
id int primary key not null,
name varchar(30) not null
);
insert into branch (id, name) values (101, 'California');
insert into branch (id, name) values (102, 'Ohio');
insert into branch (id, name) values (103, 'Delaware');
create table account (
id int primary key not null auto_increment,
balance int
);
insert into account (id, balance) values (1001, 120);
insert into account (id, balance) values (1004, 500);
insert into account (id, balance) values (1005, 45);
create table transaction (
tx_id int primary key not null auto_increment,
account_id int not null,
amount int not null,
branch_id int references branch (id)
);
insert into transaction (account_id, amount, branch_id) values
(1001, 10, 101),
(1001, 150, 101),
(1001, 200, 101),
(1001, -70, 102),
(1001, -20, 102),
(1001,-150, 102),
(1004, 50, 103),
(1004, 300, 101),
(1004, 150, 102),
(1005, 100, 102),
(1005, -55, 101);
现在查询为:
explain
select *
from account a
join transaction t4 on t4.account_id = a.id
join branch b5 on b5.id = t4.branch_id
join (select account_id as account_id from transaction t7 where amount > 0) t6
on t6.account_id = a.id
where a.balance < 7 * (
select avg(amount) from transaction t
join branch b on b.id = t.branch_id
where t.account_id = a.id
and b.name in (select name from branch b7
where name like '%a%')
)
and a.balance < 5 * (
select max(amount)
from transaction t2
join branch b2 on b2.id = t2.branch_id
where b2.name not in (select name from branch b8
where name like '%i%')
);
现在显示(传统计划):
id select_type table type key key_len ref rows filtered Extra
-- ------------------- ----- ------ ------- ------- --- ---- -------- -----
1 PRIMARY a ALL 3 33.33 Using where
1 PRIMARY t7 ALL 11 9.09 Using where
1 PRIMARY t4 ALL 11 10 Using where
1 PRIMARY b5 eq_ref PRIMARY 4 ... 1 100
5 SUBQUERY b2 ALL 3 100 Using where
5 SUBQUERY t2 ALL 11 10 Using where
6 DEPENDENT SUBQUERY b8 ALL 3 33.33 Using where
3 DEPENDENT SUBQUERY b7 ALL 3 33.33 Using where
3 DEPENDENT SUBQUERY t ALL 11 10 Using where
3 DEPENDENT SUBQUERY b eq_ref PRIMARY 4 ... 1 33.33 Using where
现在它显示所有表的信息,除了标量子查询t6
。在哪里?
答案 0 :(得分:1)
我尝试测试您的查询,但是任何表中的行数均为零。 EXPLAIN会显示“读取const表后在何处注意到”,这意味着不存在满足查询条件的行。
在测试中,我看到了t2,b2,b8,t,b,b7,t7,但没有看到a,t4,b5,t6。如果无法读取表,似乎会从EXPLAIN中省略表,因为查询条件意味着读取它们毫无意义,因为保证了它们不会匹配任何行。
我认为此子句没有任何逻辑目的
join (select max(account_id) as account_id from transaction t7) t6
on t6.account_id = a.id
如果我从查询中删除此联接,则会得到一个EXPLAIN,其中没有“不可能的位置”注释,并且它具有所有其他相关名称:
+----+--------------------+-------+------+---------------+------+---------+------+------+-------------------------------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+--------------------+-------+------+---------------+------+---------+------+------+-------------------------------------------------------------------+
| 1 | PRIMARY | a | ALL | PRIMARY | NULL | NULL | NULL | 1 | Using where |
| 1 | PRIMARY | t4 | ALL | NULL | NULL | NULL | NULL | 2 | Using where; Using join buffer (Block Nested Loop) |
| 1 | PRIMARY | b5 | ALL | PRIMARY | NULL | NULL | NULL | 2 | Using where; Using join buffer (Block Nested Loop) |
| 4 | SUBQUERY | t2 | ALL | NULL | NULL | NULL | NULL | 2 | NULL |
| 4 | SUBQUERY | b2 | ALL | PRIMARY | NULL | NULL | NULL | 2 | Using where; Using join buffer (Block Nested Loop) |
| 5 | DEPENDENT SUBQUERY | b8 | ALL | NULL | NULL | NULL | NULL | 2 | Using where |
| 2 | DEPENDENT SUBQUERY | t | ALL | NULL | NULL | NULL | NULL | 2 | Using where |
| 2 | DEPENDENT SUBQUERY | b | ALL | PRIMARY | NULL | NULL | NULL | 2 | Using where; Using join buffer (Block Nested Loop) |
| 2 | DEPENDENT SUBQUERY | b7 | ALL | NULL | NULL | NULL | NULL | 2 | Using where; FirstMatch(b); Using join buffer (Block Nested Loop) |
+----+--------------------+-------+------+---------------+------+---------+------+------+-------------------------------------------------------------------+
我没有在表中猜到任何索引,因此此EXPLAIN未显示任何优化。但是至少会出现所有相关名称。