Question

我是PHP的新手，我正在制作此页面，如果记录中有任何值，我想显示数据库中的记录。我正在使用If condition，但无法正常工作。这是我的代码：

 $active_proof=FALSE;
 while ($row_proof = mysqli_fetch_assoc($res_proof)){

if ($row_proof['proof_cat'] == "Proof of Address"  && $row_proof['proof_cat'] == "Proof of Identity"  ){

           echo '<tr>

                <td>'.$row_proof['proof_cat'].'</td>
                <td>'.$row_proof['proof_doc'].'</td>

            </tr>';
            $active_proof = TRUE;
        }else{
        $active_proof  = FALSE;
    }

    }

帮帮我！

Answer 1

确定要检查proof_cat的两个值吗？还是proof_cat和proof_doc？我认为应该...

$active_proof=FALSE;
 while ($row_proof = mysqli_fetch_assoc($res_proof)){

if (($row_proof['proof_cat'] == "Proof of Address")  && ($row_proof['proof_doc'] == "Proof of Identity"  )){

       echo '<tr>

            <td>'.$row_proof['proof_cat'].'</td>
            <td>'.$row_proof['proof_doc'].'</td>

        </tr>';
        $active_proof = TRUE;
    }else{
    $active_proof  = FALSE;
    }

 }

Answer 2

这段代码永远不会成真

if ($row_proof['proof_cat'] == "Proof of Address"  && $row_proof['proof_cat'] == "Proof of Identity"  ){

因为单列“ proof_cat”不能带有2个值。如果您是说OR，那么它将变为

if ($row_proof['proof_cat'] == "Proof of Address"  || $row_proof['proof_cat'] == "Proof of Identity"  ){

Answer 3

字符串不能等于2个不同的值，我假设您要使用逻辑或（||）而不是AND（&&）。

使用in_array的一种干净方法，尤其是使用两个以上的值时，尤其如此：

if (in_array($row_proof['proof_cat'], ["Proof of Address", "Proof of Identity"])) {

Answer 4

如果我不会误解您的代码，那么您需要此$row_proof['proof_cat']和$row_proof['proof_doc']而不是两个$row_proof['proof_cat']来检查“ 地址”和“ 身份证明”，因为这是不可能的。所以我认为您做了一些 typo ，这就是为什么它不适合您的原因。

但是，如果您只想检查$row_proof['proof_cat']的值是否相等，请使用in_array()代替

如果要检查是否等于

if (in_array($row_proof['proof_cat'], ["Proof of Address", "Proof of Identity"])) {
 //your code will goes here
}

如果是错字：为什么我将其解释为错字？

您的代码块告诉我将其视为错字。

'。$ row_proof ['proof_cat']。'

'。$ row_proof ['proof_doc']。'

 $active_proof=FALSE;
 while ($row_proof = mysqli_fetch_assoc($res_proof)){

if ($row_proof['proof_cat'] == "Proof of Address"  && $row_proof['proof_doc'] == "Proof of Identity"  ){

           echo '<tr>

                <td>'.$row_proof['proof_cat'].'</td>
                <td>'.$row_proof['proof_doc'].'</td>

            </tr>';
            $active_proof = TRUE;
        }else{
        $active_proof  = FALSE;
    }

    }

我

多个if条件php

4 个答案: