Question

如何匹配数字附近的引号：这是我所拥有的：

"Austria","AU","ULO1","185","34","4dera"

这是我需要的：

"Austria","AU","ULO1",185,34,"4dera"

这是我最近做过的事情：\"(?=\d)|(?<=\d)\"，但是这样做的问题是它也匹配以数字开头的单词，因此我无法将+，*或.放在后视或前瞻中。我试图用这样的1400行更改.csv文件。我可以用Notepad ++代替它，因为它支持正则表达式或python脚本。

Answer 1

list1 = ["Austria","AU","ULO1","185","34","4dera"]

list2 = []

for item in list1:    
    try:
        list2.append(int(item))
    except ValueError:
        list2.append(item)

应该为字符串strings返回int，为list2中的数字返回/** A test class. Detailed description of the test class * Usage: * @code * test a; * @endcode */ template<> class test { //some class }; /**@example TestExample.cpp * Simple example of how to use the test class */。

Answer 2

import re
s = '"Austria","AU","ULO1","185","34","4dera"'
print(re.sub(r'"(\d+)"',r'\1',s))

匹配"中包含的每个数字，并用不带"的数字替换。

Answer 3

在记事本++中

搜索：\"(\d+)\" 替换为：\1

Answer 4

您可以使用str.isdigit()

例如：

import csv

with open(filename, "r") as infile:
    reader = csv.reader(infile)
    for row in reader:
        print([int(i) if i.isdigit() else i for i in row])

输出：

['Austria', 'AU', 'ULO1', 185, 34, '4dera']

如何匹配仅包含数字的单词周围的引号？

4 个答案: