Question

build.gradle（省略了不必要的部分）：

apply plugin: 'java'

repositories {
    mavenCentral()
    maven {
        credentials {
            username "$mavenUser"
            password "$mavenPassword"
        }
        url "http://localhost:8081/nexus/content/groups/public"
    }
}

dependencies {
    compile("com.example:some-lib:1.0.0-RELEASE")
}

假定已配置的Maven存储库中缺少定义的依赖项。执行./gradlew clean build任务后，尽管缺少必需的依赖项，但仍成功构建了应用程序。

如果存在未解决的依赖项，是否可以将Gradle配置为失败？

涉及到：

How to make Gradle fail the build if a file dependency is not found?-提供的解决方案不适用。

Answer 1

考虑以下build.gradle（注意：故意在dependencies中指定伪造的罐子）：

apply plugin: 'java'

repositories {
    mavenCentral()
}

dependencies {
    compile("junit:junit:4.12")
    compile("junit:junitxyz:51.50")
}

task checkDependencies() {
    doLast {
        configurations.compile.each { file ->
            println "TRACER checking: " + file.name
            assert file.exists() 
        }
    }
}

compileJava.dependsOn checkDependencies

示例输出：

$ gradle -q clean compileJava

FAILURE: Build failed with an exception.
[snip]

* What went wrong:
Execution failed for task ':checkDependencies'.
> Could not resolve all files for configuration ':compile'.
   > Could not find junit:junitxyz:51.50.
     Searched in the following locations:
       - https://repo.maven.apache.org/maven2/junit/junitxyz/51.50/junitxyz-51.50.pom
       - https://repo.maven.apache.org/maven2/junit/junitxyz/51.50/junitxyz-51.50.jar

当依赖项不可用时使Gradle构建失败

1 个答案: