Question

我是python的初学者，并且以某种方式设法为One Time Pad Encryption创建代码。但是，我需要的结果只能是字母，而不是特殊的字符/符号。

import random
import string
plain=raw_input("Enter PlainText: ")
length=len(plain)
key = "".join(random.choice("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ") for i in range(length))
print "RANDOM KEY GENERATED: ",key

message=str(plain)
key1=str(key)
print "STRING 1",message
print "STRING 2",key1

arr1 = bytearray(message, 'utf-8')
print "ARRAY 1 : ",arr1

arr2 = bytearray(key, 'utf-8')
print "ARRAY 2 : ",arr2

b = bytearray(len(arr1))
for i in range(len(arr1)):
   b[i] = arr1[i] ^ arr2[i]

xored=list(b)
print "XORED LIST: ",xored

mystring=""
for char in xored:
   mystring=mystring+chr(char)
print "CIPHER TEXT IS: ",mystring

output of code

Answer 1

chr（）参数：chr()方法采用一个参数，即整数i。

chr（）返回： Unicode代码点为整数i的字符（字符串）

您只需要将mystring=mystring+chr(char)替换为mystring=mystring+str(char)。

这是您的固定代码：

import random
import string

plain=raw_input("Enter PlainText: ")
length=len(plain)
key = "".join(random.choice("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ") for i in range(length))
print "RANDOM KEY GENERATED: ",key

message=str(plain)
key1=str(key)
print "STRING 1",message
print "STRING 2",key1

arr1 = bytearray(message, 'utf-8')
print "ARRAY 1 : ",arr1

arr2 = bytearray(key, 'utf-8')
print "ARRAY 2 : ",arr2

b = bytearray(len(arr1))
for i in range(len(arr1)):
   b[i] = arr1[i] ^ arr2[i]

xored=list(b)
print "XORED LIST: ",xored

mystring=""
for char in xored:
   mystring=mystring+str(char)
print "CIPHER TEXT IS: ",mystring

哪个输出：

Enter PlainText: Foo
RANDOM KEY GENERATED:  dAD
STRING 1 Foo
STRING 2 dAD
ARRAY 1 :  Foo
ARRAY 2 :  dAD
XORED LIST:  [34, 46, 43]
CIPHER TEXT IS:  344643

如何对仅产生英语字母的python中的两个字符串进行XOR？

1 个答案: