Question

我有如下所示的字符串

Declare @string ='welcome'

我想要这样的输出

w
e
l
c
o
m
e

Answer 1

DECLARE @string VARCHAR(256) = 'welcome'
DECLARE @cnt INT = 0;

WHILE @cnt < len(@string)
BEGIN
    SET @cnt = @cnt + 1;
    PRINT SUBSTRING ( @string ,@cnt , 1 )  
END;

从本质上讲，您遍历字符串的长度。您将字符打印在循环索引的位置并打印。

Answer 2

您可以使用统计表，通常比循环更快，但是您必须自己进行测试：

declare @s varchar(200)

set     @s = 'Welcome'


;with t as (
        select  v
        from    (values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) t(v)
),
n as (
        select  row_number() over(order by (select null)) rn
        from    t t1 cross join t t2
)
select  substring(@s, rn, 1)
from    n
where   rn <= len(@s)

Answer 3

您可以使用递归CTE。

Declare @string varchar(10) ='welcome'
;with cte as 
(
select 1 as i,substring(@string,1,1) as single_char
union all
select i+1 as i,convert(varchar(1),substring(@string,i+1,i+1)) as single_char from cte where len(convert(varchar(1),substring(@string,i+1,i+1)))=1
)
select single_char From cte

垂直显示Sring

3 个答案: