Question

我正在练习ORACLE SQL。

目前我有3张桌子。

Student values = "student_id ,name"

Subjects values = "subject_id, name"

Scores values = "score, student_id, subject_id"

我正在尝试从数据库中检索以下信息。

学生姓名，科目的名称和ID，最后是具有student_id“ 34560”的分数。

SELECT scores.score, 
       scores.subject_id, 
       student.name, 
       subject.subject_id, 
       subject.name
  FROM scores 
 INNER JOIN students 
   ON scores.student_id = '34560'
INNER JOIN subject
   ON /* and here's where i'm lost*/

有没有一种方法可以将查询的第一部分全部合并在一起，即我将Student_id =“ 34560”的学生列表称为学生列表，然后查询该列表以查看其是否与subject_id匹配？

Answer 1

使用in运算符获取学生ID列表

    SELECT sc.score, sc.subject_id, 
   st.name, sb.subject_id, sb.name
        FROM scores sc
        INNER JOIN students  st
        ON sc.student_id = st.student_id
        INNER JOIN subject sb
        ON sc.subject_id=sb.subject_id    
      where sc.student_id in ('34560','add_anotherstudentid','add_anotherstudentid') //you can add multiple student id

具有2个以上表的SQL查询

1 个答案: