像按钮一样喜欢instagram崩溃后按

Question

我向我的应用程序添加了新选项，用户可以喜欢这些地方，但是当我按类似Button的按钮时，我会崩溃[线程1：致命错误：在展开一个可选值时意外发现nil]

代码： tableViewCell按钮

@IBAction func likePressed(_ sender: Any) {
    self.likeBtn.isEnabled = false
    let ref = Database.database().reference()
    //let key = ref.childByAutoId().key
    let keyToPost = ref.child("Restaurant").childByAutoId().key


    ref.child("Restaurant").child(self.postID).observeSingleEvent(of: .value, with: { (snapshot) in
                          //.child(self.id)
        if let post = snapshot.value as? [String : AnyObject] {
            let updateLikes: [String : Any] = ["peopleWhoLike/\(keyToPost)" : Auth.auth().currentUser!.uid]
            ref.child("Restaurant").child(self.postID).updateChildValues(updateLikes, withCompletionBlock: { (error, reff) in

                if error == nil {
                    ref.child("Restaurant").child(self.postID).observeSingleEvent(of: .value, with: { (snap) in
                        if let properties = snap.value as? [String : AnyObject] {
                            if let likes = properties["peopleWhoLike"] as? [String : AnyObject] {
                                let count = likes.count
                                self.likeLabel.text = "\(count) Likes this place"

                                let update = ["likes" : count]
                                ref.child("Restaurant").child(self.postID).updateChildValues(update)

                                self.likeBtn.isHidden = true
                                self.unlikeBtn.isHidden = false
                                self.likeBtn.isEnabled = true
                                print("Likes")
                            }
                        }
                    })
                }
            })
        }


    })

    ref.removeAllObservers()
}

错误屏幕截图

第二个屏幕截图

有人可以帮助我吗，谢谢！

Answer 1

let updateLikes: [String : Any] = ["peopleWhoLike/\(keyToPost)" : Auth.auth().currentUser!.uid]

可能没有currentUser->强制拆开像崩溃您的应用程序一样，我会尽可能避免它们。 您在哪里验证当前用户？

您如何登录用户：

然后在您的代码之前，我要做类似的事情：

guard let userUID = Auth.auth().currentUser?.uid else {
return
}