Question

我有两个工人同时工作，目前他们都在同一时间接受相同的工作。我给人的印象是，当工作人员A运行作业时，工作人员B将在队列中接收下一个作业。每个作业大约需要10秒钟才能完成。我该怎么做？

我已将代码简化为：（假设客户端两次相隔两次被调用两次）

客户

$client = new GearmanClient();
$client->addServer();

$client->doBackground("my_task");

工作者

$worker = new GearmanWorker();
$worker->addServer();
$worker->addFunction("my_task", "my_task_fn");

while($worker->work());

function my_task_fn($job) {
    echo $job->handle(); // both workers show same job #, I want each worker getting a different job
    sleep(10);
}

Answer 1

您所描述的内容不应该发生，我提供了一个示例供您了解。直到工作人员响应并返回响应，客户端脚本才会完成。但是您可以通过将'doNormal'更改为'doBackground'来轻松适应。在您的worker函数中放置一个睡眠计数器以减慢该worker的速度，并使您的客户端处于循环状态以创建大量作业，以查看该进程的工作进展情况。

客户代码

// Create our client object
$client = new GearmanClient();

// Add a server
$client->addServer(); // by default host/port will be "localhost" & 4730

echo "Sending job\n";

// Send reverse job
$result = $client->doNormal("reverse", "Hello!");
if ($result) {
    echo "Success: $result\n";
}

工人代码

// Create our worker object
$worker = new GearmanWorker();

// Add a server (again, same defaults apply as a worker)
$worker->addServer();

// Inform the server that this worker can process "reverse" function calls
$worker->addFunction("reverse", "reverse_fn");

while (1) {
    print "Waiting for job...\n";
    $ret = $worker->work(); // work() will block execution until a job is delivered
    if ($worker->returnCode() != GEARMAN_SUCCESS) {
        break;
    }
}

// A much simple reverse function
function reverse_fn(GearmanJob $job) {
    $workload = $job->workload();
    echo "Received job: " . $job->handle() . "\n";
    echo "Workload: $workload\n";
    $result = strrev($workload);
    echo "Result: $result\n";
    return $result;
}

多名Gearman工人获得同一工作

1 个答案: