Question

我在一个csv文件中有一个URL列表，我需要在for eachUrl in final_url:中运行它们，但是我不断收到回溯错误，因为我发现当我从下面的代码打印URL时，它也是打印出['https://www.anyurl.com']而不仅仅是网址。我尝试运行一个循环来替换[' ']，但收到回溯错误AttributeError: 'list' object has no attribute 'replace'。我如何打开csv并仅拉出URL并将其放入列表中，而不将其放入另一个列表中的列表中？

import csv
with open('urls_for_BrightScope_Form5500s.csv', 'r') as r:
    reader = csv.reader(r)
    for row in reader:
        final_urls.append(row)
        print(len(final_urls))

Output from final_url list: ['https://www.brightscope.com/401k-rating/372254/Merritt-Brothers-Lumber-Company/377291/Merritt-Brothers-Lumber-Co-401K-Profit-Sharing-Plan/'], ['https://www.brightscope.com/401k-rating/255132/Merritt-Club-Management-Inc/259235/Merritt-Club-Management-Inc-401K-Profit-Sharing-Plan-And-Trust/'], ['https://www.brightscope.com/401k-rating/404751/Merritt-Equipment-Co/410055/Merritt-Equipment-Co-401K-Profit-Sharing-Plan/'], ['https://www.brightscope.com/401k-rating/256405/Merritt-Hospitality-Llc/260527/Merritt-Hospitality-401K-Plan/']

Answer 1

假设输入文件（urls_for_BrightScope_Form5500s.csv）只是纯文本文件，每行只有一个URL，我想您应该阅读这些行，而无需任何csv库：

with open('urls_for_BrightScope_Form5500s.csv', 'rt') as f:
    final_urls = [line.strip() for line in f]

Answer 2

假设一行中只有一个网址，您也可以只使用行读取，例如：

with open('urls_for_BrightScope_Form5500s.csv', 'r') as fr:
    final_urls = [url.strip() for url in fr]

Python CSV阅读器在列表内创建列表

2 个答案: