我已经成功返回了我要搜索的对象(商店),但是现在我想遍历服务员数组并为商店打印服务员。我不能使用jQuery $ each()进行迭代。我能做什么?谢谢,谢谢您的协助。
totals.js(我的服务)
<?php
//getting the data from the Database
$aVar = mysqli_connect('localhost','root','','socialnetwork');
$usernameaccount = mysqli_query($aVar, "SELECT username FROM users WHERE username = '$username'")->fetch_array()[0];
$age = mysqli_query($aVar, "SELECT p.age FROM profiles p, users u WHERE u.username = '$username' AND u.id = p.id")->fetch_array()[0];
$gender = mysqli_query($aVar, "SELECT p.gender FROM profiles p, users u WHERE u.username = '$username' AND u.id = p.id")->fetch_array()[0];
$description = mysqli_query($aVar, "SELECT p.description FROM profiles p, users u WHERE u.username = '$username' AND u.id = p.id")->fetch_array()[0];
//after getting the data i insert them into a variable with some html code:
$outputusername = '<h2>'.$usernameaccount.'<hr></h2>';
$outputage = '<h2>'.$age.'<hr></h2>';
$outputgender = '<h2>'.$gender.'<hr></h2>';
$outputdescription = '<h2>'.$description.'<hr></h2>';
?>
tender-total-data.json
export const baseUrl = '/src/areas/store-totals/services/tender-total-data.json';
export const all = args =>
// http.post.standard(baseUrl + 'orders/tenderTotals', {}, args);
http.get(baseUrl).
then(function onSuccess(response) {
console.log("The response is :" , response);
}).
catch(function onError(response) {
console.log(response);
});
答案 0 :(得分:0)
如果要获取特定商店的服务员,可以按以下方式使用array.find,
let data ={
"stores": [
{
"storeName": "Master Bistro",
"storeId": "3046",
"attendants": [
{
"attendantName": "Janis Joplin",
"attendantId": "9784526",
"total": 2000,
"tenderTotal": {
"Cash": 500,
"TC": 0,
"UOD": 500,
"MC": 250,
"VI": 250,
"AX": 250,
"DI": 250,
"JC": 0,
"DC": 0,
"UOP": 0,
"GN": 0,
"UOGC": 0,
"HOTEL": 0,
"NCTNCG": 0
}
},
{
"attendantName": "David Bowie",
"attendantId": "2589456",
"total": 14675,
"tenderTotal": {
"Cash": 175,
"TC": 0,
"UOD": 100,
"MC": 9500,
"VI": 3500,
"AX": 550,
"DI": 850,
"JC": 0,
"DC": 0,
"UOP": 0,
"GN": 0,
"UOGC": 0,
"HOTEL": 0,
"NCTNCG": 0
}
},
{
"attendantName": "Michael Jackson",
"attendantId": "5478264",
"total": 15599,
"tenderTotal": {
"Cash": 250,
"TC": 0,
"UOD": 80,
"MC": 5624,
"VI": 6895,
"AX": 2500,
"DI": 250,
"JC": 0,
"DC": 0,
"UOP": 0,
"GN": 0,
"UOGC": 0,
"HOTEL": 0,
"NCTNCG": 0
}
}
],
"message": "Store totals for 08/20/2018",
"date": "08/20/2018"
},
{
"storeName": "The Master Marketplace",
"storeId": "3047",
"attendants": [
{
"attendantName": "Dirk Novitski",
"attendantId": "9784527",
"total": 2000,
"tenderTotal": {
"Cash": 500,
"TC": 0,
"UOD": 500,
"MC": 250,
"VI": 250,
"AX": 250,
"DI": 250,
"JC": 0,
"DC": 0,
"UOP": 0,
"GN": 0,
"UOGC": 0,
"HOTEL": 0,
"NCTNCG": 0
}
},
{
"attendantName": "Carmello Anthony",
"attendantId": "2589458",
"total": 14675,
"tenderTotal": {
"Cash": 175,
"TC": 0,
"UOD": 100,
"MC": 9500,
"VI": 3500,
"AX": 550,
"DI": 850,
"JC": 0,
"DC": 0,
"UOP": 0,
"GN": 0,
"UOGC": 0,
"HOTEL": 0,
"NCTNCG": 0
}
},
{
"attendantName": "Stevie Wonder",
"attendantId": "5478266",
"total": 15599,
"tenderTotal": {
"Cash": 250,
"TC": 0,
"UOD": 80,
"MC": 5624,
"VI": 6895,
"AX": 2500,
"DI": 250,
"JC": 0,
"DC": 0,
"UOP": 0,
"GN": 0,
"UOGC": 0,
"HOTEL": 0,
"NCTNCG": 0
}
}
],
"message": "Store totals for 08/22/2018",
"date": "08/21/2018"
}
]
};
let attendants = data.stores.find(store=>store.storeId == 3047).attendants;
attendants.forEach( (element) => {
console.log(element);
});
答案 1 :(得分:0)
要迭代数组元素,可以使用诸如map或forEach之类的函数。如果使用map,则迭代逻辑将类似于:
attendants.map((item) => {
console.log(item);
});