Question

我正在使用以下代码在设备上构建要在ListActivity上显示的电子邮件地址列表。目前我可以检索确定的电子邮件地址，但它们会以null (email@address.com)而不是name (email@address.com)的形式出现，这并不理想。我正在使用的代码也应该检索名称：

Cursor c = getContentResolver().query(Email.CONTENT_URI,
        new String[]{Email.CONTACT_ID, Email.DISPLAY_NAME, Email.DATA},
        null, null, null);

addresses = new String[c.getCount()];
try{
    c.moveToFirst();
    for(int i = 0;i<c.getCount();i++){
        addresses[i] = c.getString(1) + " (" + c.getString(2) + ")";
        c.moveToNext();
    }
} finally {
    c.close();
}

有谁知道我做错了什么？

Answer 1

我已经使用了这个（绝对适用于不可思议的Android 2.2; 2.3上没有承诺）。

String nameAndEmailOrder = "lower(" + ContactsContract.Data.DISPLAY_NAME + ") ASC";
String[] nameAndEmailProjection = new String[] {
        ContactsContract.Data.DISPLAY_NAME,
        ContactsContract.CommonDataKinds.Email.DATA }

    Cursor emails = activity.managedQuery(
            ContactsContract.CommonDataKinds.Email.CONTENT_URI,
            nameAndEmailProjection, null, null, nameAndEmailOrder);

    emails.moveToFirst();
    int nameColumn = emails.getColumnIndex(
            ContactsContract.Data.DISPLAY_NAME);
    int emailColumn = emails.getColumnIndex(
                    ContactsContract.CommonDataKinds.Email.DATA);
    do {
        Log.d("test", String.format("%s (%s)", emails.getString(nameColumn), emails.getString(emailColumn)));
    } while (emails.moveToNext());

Answer 2

尝试此查询：

Cursor c = managedQuery(ContactsContract.CommonDataKinds.Email.CONTENT_URI,
            new String[]{ContactsContract.Contacts._ID, ContactsContract.Contacts.DISPLAY_NAME, ContactsContract.CommonDataKinds.Email.DATA},
            null, null, null);

Answer 3

尝试此查询：

Cursor c = getContentResolver().query(Data.CONTENT_URI,
        new String[]{Data.CONTACT_ID, Data.DISPLAY_NAME, Email.ADDRESS},
        Data.MIMETYPE + "=?", new String[] {Email.CONTENT_TYPE}, null);

addresses = new String[c.getCount()];
try{
    c.moveToFirst();
    for(int i = 0;i < c.getCount();i++){
        addresses[i] = c.getString(1) + " (" + c.getString(2) + ")";
        c.moveToNext();
    }
} finally {
    c.close();
}

注意：Email.ADDRESS将转换为Data.DATA1。

电子邮件ContentResolver的问题

3 个答案: