using A = System.Console;
public void point()
{
int hour, minute;
A.Write("Enter Time (HH:MM) = ");
hour = A.Read();
A.Write(":");
minute = A.Read();
}
我希望它像
“输入时间(HH:MM)= 12(小时输入):49(分钟输入)”
但是它像
“输入时间(HH:MM)= 12(小时输入)
:49(分钟输入)
答案 0 :(得分:3)
最简单的方法(假设您正在从控制台中读取,并且用户将输入小时,然后按Enter
,然后输入分钟并按Enter
):
static void Main(string[] args)
{
int hour = 0, minute = 0;
const int MAX_NUMBER_OF_DIGITS = 2 ;
Console.Write("Enter Time (HH:MM) = ");
// store cursor position
int cursorLeft = Console.CursorLeft;
int cursorTop = Console.CursorTop;
// use ReadLine, else you will only get 1 character
// i.e. number more than 1 digits will not work
hour = int.Parse(Console.ReadLine());
Console.SetCursorPosition(cursorLeft + MAX_NUMBER_OF_DIGITS , cursorTop);
Console.Write(":");
minute = int.Parse(Console.ReadLine());
// Nitpickers! purposefully not using String.Format,
// or $, since want to keep it simple!
Console.Write("You entered: " + hour + ":" + minute);
}
输出:
输入时间(HH:MM)= 17:55
您输入的是:17:55
尽管我希望向您推荐这样一种更好和更少出错的方式(用户输入HH:MM并按一次Enter
,即输入一个包含{{1 }},即冒号):
:
答案 1 :(得分:1)
假设A是控制台,您可以这样做:
static void Main()
{
int hour, minute;
char[] hourChars = new char[2];
Console.Write("Enter Time (HH:MM) = ");
hourChars[0] = Console.ReadKey().KeyChar;
hourChars[1] = Console.ReadKey().KeyChar;
var hourString = new String(hourChars);
hour = int.Parse(hourString);
Console.Write(":");
minute = Console.Read();
}
答案 2 :(得分:0)
假设A是标准的c#Console
,则可以使用ReadKey
代替Read
ReadKey
一次只能读取一个字符,但不会强迫您按Enter键,这是换行的原因。
static void Main()
{
char h1, h2, m1, m2;
Console.Write("Enter Time (HH:MM) = ");
h1 = Console.ReadKey().KeyChar;
h2 = Console.ReadKey().KeyChar;
Console.Write(":");
m1 = Console.ReadKey().KeyChar;
m2 = Console.ReadKey().KeyChar;
}
我将保留实际值解析作为练习。