我可以使用parseInt解决此问题吗?控制流

时间:2018-08-30 16:09:29

标签: javascript

提示用户输入一个大于100但小于2000的数字,并将其存储为名为user的变量。

写一条if语句,检查用户是否大于100且小于2000。

如果是,则应将message1分配给名为result的变量。如果不是,则应改为分配message2。

var user = prompt("Give me a number between 100 and 2000");
var message1 = 'You are amazingly correct!';
var message2 = 'Awww, it looks like that number is not correct. Try again!';

var result = message1;
function 
if(){
 console.log(result);
}
else (sonsole.log(message2));

1 个答案:

答案 0 :(得分:0)

var user = prompt("Give me a number between 100 and 2000");
var message1 = 'You are amazingly correct!';
var message2 = 'Awww, it looks like that number is not correct. Try again!';


if(user <2000 && user >100){
console.log(message1);
}else{
console.log(message2);
}