Question

我需要有关此程序的帮助。浮点数组购买[2]的值为90.50，但是当我运行代码时，它从90.50变为90.5010.990000。为什么？采购[0]和采购[1]打印罚款。任何帮助将不胜感激。

#include <stdio.h>

int main() {
    float purchases[3] = {10.99, 14.25, 90.50};
    float total = 0;
    int k;

    //Total the purchases
    printf("%.2f %.2f %.2f", purchases[0], purchases[1], purchases[2]); // Just so I know whats going on

    for (k = 0; k < 3; k++) {
        total += purchases[k];
        printf("%f\n", total); // Just so I know whats going on
        printf("%d\n", k);  // Just so I know whats going on
    }

    printf("Purchases total is %6.2f\n", total);
}

Answer 1

打印purchases数组的内容时，不打印换行符。因此，当您首次在循环中打印total时，它会出现在同一行。

添加换行符：

printf("%.2f %.2f %.2f\n", purchases[0], purchases[1], purchases[2]);

输出：

10.99 14.25 90.50
10.990000
0
25.240000
1
115.739998
2
Purchases total is 115.74

Answer 2

此：

90.5010.990000

是90.50，然后是10.990000。您忘记了使用换行符。

更改此：

printf("%.2f %.2f %.2f", ..

对此：

printf("%.2f %.2f %.2f/n", ..

Answer 3

感谢@StoryTeller。没有新行！男生错误的权利。

应该是：

printf("%.2f %.2f %.2f\n", purchases[0], purchases[1], purchases[2]);

很抱歉打扰大家。

#include <stdio.h>

int main() {
    float purchases[3] = {10.99, 14.25, 90.50};
    float total = 0;
    int k;

    //Total the purchases
    printf("%.2f %.2f %.2f\n", purchases[0], purchases[1], purchases[2]); // Just so I know whats going on

    for (k = 0; k < 3; k++) {
        total += purchases[k];
        printf("%f\n", total); // Just so I know whats going on
        printf("%d\n", k);  // Just so I know whats going on
    }

    printf("Purchases total is %6.2f\n", total);
}

C编程为什么浮点值改变

3 个答案: