不兼容的类型：int不能转换为Drawable

Question

我正在尝试在android studio上制作气泡选择器动画，但出现此错误：

  

错误：不兼容的类型：int无法转换为Drawable

这表明该行中存在错误

PickerItem item = new PickerItem(name[i],colors[i],Color.WHITE,getResources().getDrawable(images[i]));

当我将鼠标悬停在那条线上时，它会显示类似这样的内容

这是Java代码：

import android.graphics.Color;
import android.graphics.drawable.Drawable;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.widget.Toast;

import com.igalata.bubblepicker.BubblePickerListener;
import com.igalata.bubblepicker.model.PickerItem;
import com.igalata.bubblepicker.rendering.BubblePicker;

import java.util.ArrayList;

    public class  MainActivity extends AppCompatActivity {
        BubblePicker bubblePicker;
        int i;
        String[] name={
                "anime1","anime2","anime3","anime4","anime5","anime6"

        };
        int[] images={
                R.drawable.x1,
                R.drawable.x2,
                R.drawable.x3,
                R.drawable.x4,
                R.drawable.x5,
                R.drawable.x6


    };
    int[] colors={
            Color.parseColor("#1A237E"),
            Color.parseColor("#6200EA"),
            Color.parseColor("#004D40"),
            Color.parseColor("#1A237E"),
            Color.parseColor("#880E4F"),
            Color.parseColor("#B71C1C")
    };
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        bubblePicker = (BubblePicker) findViewById(R.id.bubble);
        ArrayList<PickerItem> listItems = new ArrayList<>();


        for(int i = 0; i<name.length; i++)
        {
            //Drawable drawable= getResources().getDrawable(images[i]);
            PickerItem item = new PickerItem(name[i],colors[i],Color.WHITE,getResources().getDrawable(images[i]));
            listItems.add(item);

        }
        bubblePicker.setItems(listItems);
        bubblePicker.setListener(new BubblePickerListener() {
            @Override
            public void onBubbleSelected(PickerItem pickerItem) {
                Toast.makeText(getApplicationContext(),""+pickerItem.getTitle()+"selected",Toast.LENGTH_SHORT).show();

            }

            @Override
            public void onBubbleDeselected(PickerItem pickerItem) {
                Toast.makeText(getApplicationContext(),""+pickerItem.getTitle()+"Deselected",Toast.LENGTH_SHORT).show();


            }
        });


    }

    @Override
    protected void onResume(){
        super.onResume();
        bubblePicker.onResume();
    }
    @Override
    protected void onPause(){
        super.onPause();
        bubblePicker.onPause();
    }
}

Answer 1

我猜您为构造函数使用了错误的参数顺序，应该是：

PickerItem item = new PickerItem(name[i], getResources().getDrawable(images[i]), true/false, Color.WHITE);

或者类似的东西，不知道您的要求是什么。

Answer 2

我认为您感到困惑。 PickerItem 构造函数按以下特定顺序需要这四个参数：

1. 字符串
2. 可绘制
3. 布尔值
4. 整数

因此，它可能看起来像这样：

PickerItem item = new PickerItem(name[i], context.getDrawable(images[i]), hasIconOnTop, colors[i]);

其中hasIconOnTop是一个布尔值值。

Answer 3

PickerItem构造函数具有以下签名

new PickerItem (String, Drawable, boolean, Integer)

，您将其用作：

new PickerItem (String, int, int, Drawable)

您应该尝试使用：

PickerItem item = new PickerItem(name[i],getResources().getDrawable(images[i]),true, colors[i]);