java.time

Question

我正在使用Windows 10计算器等日期计算应用程序您选择开始和结束日期的地方并计算月份和年份的天数

  public String differenceInDates(){
                Date start_date = convertStringToDate("2017-04-24");
                Date end_date = convertStringToDate("2018-07-24");
                long different = this.end_date.getTime() - this.start_date.getTime();

                        long millisInSeconds = 1000;
                        long millisInMinutes = millisInSeconds * 60;
                        long millisInHours = millisInMinutes * 60;
                        long millisInDay = millisInHours *24;

                        long elapsedDays = different / millisInDay;
                        different = different % millisInDay;

                        long elapsedHours = different / millisInHours;
                        different = different % millisInHours;

                        long elapsedMinutes = different / millisInMinutes;
                        different = different % millisInMinutes;

                        long elapsedSeconds = different / millisInSeconds;
                        if (elapsedHours == 0){
                            return String.valueOf("days"+elapsedDays+":"+":"+elapsedMinutes+":"+elapsedSeconds);
                        }
                        if (elapsedMinutes == 0){
                            return String.valueOf("days"+elapsedDays+":"+":"+elapsedHours+":"+elapsedSeconds);
                        }
                        if (elapsedHours == 0 && elapsedMinutes == 0){
                            return String.valueOf("days"+elapsedDays);
                        }
                        return String.valueOf("days"+elapsedDays+":"+" Hours"+elapsedHours+":"+" Minutes"+elapsedMinutes+":"+elapsedSeconds);
                }

                private Date convertStringToDate(String strDate) throws ParseException {
                        SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd");
                        Date date = simpleDateFormat.parse(strDate);
                        return date;
                    }

我想要这样的答案

1年3个月

Answer 1

java.time

如果您可以使用LocalDate和Period，那么这很简单：

LocalDate date1 = LocalDateTime.of(2018, Month.SEPTEMBER, 2, 13, 40);
LocalDate date2 = LocalDateTime.of(2018, Month.SEPTEMBER, 2, 13, 40);
Period period = Period.between(date1, date2);
System.out.println(period.getYears() + " year " + period.getMonths() + " months");

Answer 2

您可以使用以下代码：

SimpleDateFormat formatter = new SimpleDateFormat("dd-MM-yyyy");
            String CURRDATE = "16-07-1991";
            String EFFDATE = "28-08-2018";

            Date startdate = null;
            Date enddate = null;
            try {
                startdate = formatter.parse(CURRDATE);
                enddate = formatter.parse(EFFDATE);
            } catch (ParseException e) {
                e.printStackTrace();
            }

            Calendar startCalendar = new GregorianCalendar();
            startCalendar.setTime(startdate);

            Calendar endCalendar = new GregorianCalendar();
            endCalendar.setTime(enddate);

            int monthCount = 0;
            int firstDayInFirstMonth = startCalendar.get(Calendar.DAY_OF_MONTH);
            startCalendar.set(Calendar.DAY_OF_MONTH, 1);
            endCalendar.add(Calendar.DAY_OF_YEAR, -firstDayInFirstMonth + 1);

            while (!startCalendar.after(endCalendar)) {
                startCalendar.add(Calendar.MONTH, 1);
                ++monthCount;
            }

            startCalendar.add(Calendar.MONTH, -1);
            --monthCount;
            int remainingDays = 0;
            while (!startCalendar.after(endCalendar)) {
                startCalendar.add(Calendar.DAY_OF_YEAR, 1);
                ++remainingDays;
            }

            startCalendar.add(Calendar.DAY_OF_YEAR, -1);
            --remainingDays;

            int lastMonthMaxDays = endCalendar.getActualMaximum(Calendar.DAY_OF_MONTH);
            if (remainingDays >= lastMonthMaxDays) {
                ++monthCount;
                remainingDays -= lastMonthMaxDays;
            }

            int diffMonth = monthCount % 12;
            int diffYear = monthCount / 12;
            int diffDay = remainingDays;

            System.out.println(diffYear + " Year(s) and " + diffMonth + " Month(s) and " + diffDay + " Day(s)");

结果是：

27 Year(s) and 1 Month(s) and 12 Day(s)

计算开始日期和结束日期之间经过的天，月和年

2 个答案:

java.time