以下代码成功地动态创建了两个按钮,我不知道是如何在单击时使按钮打开不同的文件。
我想念什么?
<ItemsControl ItemsSource="{Binding DataButtons}">
<ItemsControl.ItemTemplate>
<DataTemplate>
<Button Content="{Binding ButtonName}"
Command="{Binding ButtonCommand}"
CommandParameter="{Binding FilePath}"/>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
namespace DynamicControlsMvvmLight.ViewModel
{
public class MainViewModel : ViewModelBase
{
private readonly ObservableCollection<ButtonModel> _dataButtons = new ObservableCollection<ButtonModel>();
public ObservableCollection<ButtonModel> DataButtons { get { return _dataButtons; } }
private ICommand _buttonCommand;
public ICommand ButtonCommand
{
get {
if (_buttonCommand == null) {
_buttonCommand = new RelayCommand<object>(CommandExecute, CanCommandExecute);
}
return _buttonCommand;
}
}
public MainViewModel()
{
ButtonModel data1 = new ButtonModel("Button 1", ButtonCommand, "c:/Folder/File1.PDF");
ButtonModel data2 = new ButtonModel("Button 2", ButtonCommand, "c:/Folder/File2.PDF");
DataButtons.Add(data1);
DataButtons.Add(data2);
}
private void CommandExecute(object FilePath)
{
ButtonModel button = FilePath as ButtonModel;
System.Diagnostics.Process.Start(button.FilePath);
}
private bool CanCommandExecute(object FilePath)
{
Console.WriteLine("CanCommandExecute Method...");
return true;
}
}
}
namespace DynamicControlsMvvmLight.Model
{
public class ButtonModel
{
public string ButtonName { get; set; }
public ICommand ButtonCommand { get; set; }
public string FilePath { get; set; }
public ButtonModel(string buttonName, ICommand buttonCommand, string filePath)
{
ButtonName = buttonName;
ButtonCommand = buttonCommand;
FilePath = filePath;
}
}
}
答案 0 :(得分:1)
RelayCommand
希望收到CommandParameter
,在这种情况下为string
。
代码必须类似于:
public ICommand ButtonCommand
{
get
{
if (_buttonCommand == null)
{
_buttonCommand = new RelayCommand<string>(CommandExecute, CanCommandExecute);
}
return _buttonCommand;
}
}
和
private void CommandExecute(string filePath)
{
System.Diagnostics.Process.Start(filePath);
}