python中的简单列表试图在两者之间建立新的界限

Question

r=[]  
x='hi'  
y='there'  
z='how are you?'  
for i in range(4):  
    r.append(x)
    r.append(y)
    r.append('\n')
    r.append(z)
print(r)  

当前结果：

['hi', 'there', '\n', 'how are you ?', 'hi', 'there', '\n', 'how are you ?', 'hi', 'there', '\n', 'how are you ?', 'hi', 'there', '\n', 'how are you ?']

它不会换行。有人可以帮我这个简单的程序吗？

预期输出：

hi there  
how are you?   
hi there  
how are you?  
...

Answer 1

您需要在循环末尾附加另一个换行符，并使用join方法打印结果

r=[]  
x='hi'  
y='there'  
z='how are you?'  
for i in range(4):  
    r.append(x)
    r.append(y)
    r.append('\n')
    r.append(z)
    r.append('\n')
print(r)
print(" ".join(r)) 

输出

  

嗨，在那里
    你好吗？
    嗨
    你好吗？
    嗨
    你好吗？
    嗨
    你好吗？

Answer 2

您应该将字符串连接到输出字符串，而不是附加到列表：

output = ''
x = 'hi'  
y = 'there'  
z = 'how are you?'  
for i in range(4):  
    output += x + ' ' + y + '\n' + z + '\n'
print(output)  

给出：

hi there
how are you?
hi there
how are you?
hi there
how are you?
hi there
how are you?