Question

我需要将日期与今天的日期进行匹配（=或>），而当前小时则使用PHP与用户定义的值进行匹配。我在下面解释我的代码。

<?php
$cdate='2018-08-27 00:00:00';
$today=date("Y-m-d h:i:s");
$cdate1=strtotime($cdate);
$today1=strtotime($today1);
if ($today1 > $cdate1) {
    echo 'greater day';
}else{
    echo 'lesser day';
}
?>

上面的代码无法正常工作。我的要求是比较

1）今天的日期等于或大于定义的日期

2）定义的小时等于用户定义的小时。

Answer 1

您可以使用DateTime :: createFromFormat比较日期和时间。

尝试：

date_default_timezone_set('UTC'); // It is important to set same timezone as the input date for comparison

$currentDateTime = new DateTime(); // current DateTime object

$cdate='2018-08-29 07:50:59'; // input date
$cdateFormat = 'Y-m-d H:i:s'; // input date format

$cdateDateTime = DateTime::createFromFormat($cdateFormat, $cdate);

$dateFormat = 'Y-m-d'; //only date format
$cdateOnlyDate = $cdateDateTime->format($dateFormat);
$currentDateTimeOnlyDate = $currentDateTime->format($dateFormat);


if ($currentDateTimeOnlyDate < $cdateOnlyDate) {
    echo "lesser date";
} elseif ($currentDateTimeOnlyDate > $cdateOnlyDate) {
    echo "greater date";
} else {
    echo "same date ";

    $timeFormat = 'H:i:s'; //only time format
    $currentDateTimeOnlyTime = $currentDateTime->format($timeFormat);
    $cdateOnlyTime = $cdateDateTime->format($timeFormat);
    echo "<br /> Check the var_dump below to ensure correct time w.r.t timezone<br />";
    var_dump($currentDateTimeOnlyTime, $cdateOnlyTime);
    echo "<br />";
    if ($currentDateTimeOnlyTime < $cdateOnlyTime) {
        echo "lesser time";
    } elseif ($currentDateTimeOnlyTime > $cdateOnlyTime) {
        echo "greater time";
    } else {
        echo "same time ";
    }
}

输出：https://3v4l.org/Oe6b3

Answer 2

类似的事情会起作用

<?php
    echo var_dump($date = getdate());
      if($date['year'] >= $user_year_value && $date['mon'] >= $user_month_value && $date['mday'] >= $user_day_value){
          //** Do something. DOn't forget to set timezone */
      }

?>

SQL也可以为您做到这一点 getdate（）;还会给你小时和分钟。

但是，实际上，如果您打算将其用于约会或事件，则SQL可以完成这项工作。

Answer 3

有

的问题

$today1=strtotime($today1);

$ today1不是定义变量，因此应进行如下更改

$today1=strtotime($today);

然后它起作用。

Answer 4

为什么不使用DateTime objects使其更简单？

附加：Relative terms代表strtotime，DateTime和date_create。

我迅速为您创建了一些带有一些注释的示例。

<?php

$today = new DateTime('today'); // comes with today's date and 00:00:00 for time
$now = new DateTime('now');     // comes with today's date and current time

if ($now > $today) {
    echo 'Now is later than the day\'s start... <br />';
}

echo  '<hr />';

$testDates = [
    '2018-08-07',
    '2018-08-31',
];

// Compare with "now" -> ignores time
foreach ($testDates as $testDate) {
    // Create new DateTime based on given string and sets time to 00:00:00
    $testDate = (new DateTime($testDate))->setTime(0, 0, 0);

    if ($testDate > $today) {
        echo 'Test date "' . $testDate->format('Y-m-d') . '" is greater than today: ' . $today->format('Y-m-d') . '<br />';
    }
}

echo  '<hr />';

$testDatesWithTime = [
    '2018-08-07 12:33:33',
    '2018-08-29 08:00:00', // Today - has already been
    '2018-08-29 22:00:00', // Today - is yet to come
    '2018-08-30 22:00:00',
];

// Compare with "now" -> take time into account
foreach ($testDatesWithTime as $testDate) {
    // Create new DateTime based on given string and sets time
    $testDate = new DateTime($testDate);

    if ($testDate > $now) {
        echo 'Test date "' . $testDate->format('Y-m-d H:i:s') . '" is greater than today: ' . $now->format('Y-m-d H:i:s') . '<br />';
    }
}

上面的输出

Now is later than the day's start...

Test date "2018-08-31" is greater than today: 2018-08-29

Test date "2018-08-29 22:00:00" is greater than today: 2018-08-29 09:55:06
Test date "2018-08-30 22:00:00" is greater than today: 2018-08-29 09:55:06

Answer 5

第一个问题已被多次提及：$ today1 未定义
第二个问题是在时间格式中使用h：永远不会那样解决
此外，日期格式如您正在使用的一个，它顺序良好，字符串比较顺序是与时间顺序相同。因此，无需转换为时间对象。

这个版本当然不仅可以比较小时，还可以比较分钟和秒，如果有问题的话，只需剪断字符串即可。

<?php
$cdate='2018-08-29 10:00:00';
$today=date("Y-m-d H:i:s");

if ($today > $cdate) {
    echo 'greater day';
} else {
    echo 'lesser day';
}
?>

Answer 6

您实际上并不需要一个函数，但这仅仅是为了进行多次测试：

function compareDate($cdate){
    $today=date("Y-m-d h:i:s");
    $cdate=array_chunk(date_parse($cdate),3,true);//use date parse to handle any valid date format
    $today=array_chunk(date_parse($today),3,true);
    $cday=join('-',$cdate[0]);//get only the day without the time
    $thisday=join('-',$today[0]);
    $cHour=$cdate[1]['hour'];//get only the hour as it is the OP requirement
    $thishour=$today[1]['hour'];
    if ($thisday > $cday)
    {
        echo '<br>greater day<br>';
    }
    elseif($thisday == $cday)//if this day == user defined date compare only Hour then
    {
        echo '<br>same day<br>';
        if ($thishour > $cHour)
        {
            echo '<br>greater hour<br>';
        }
        elseif($thishour == $cHour)
        {
            echo '<br>same hour<br>';
        }else
        {
            echo '<br>lesser hour<br>';
        }
    }
    else
    {
        echo '<br>lesser day<br>';
    }
}
compareDate('2018-08-27 00:00:00');

输出：

greater day

然后

compareDate(date("Y-m-d h:i:s"));

输出：

same day 
same hour

使用PHP无法将日期与时间匹配

6 个答案: