Question

我的查询是

SELECT MONTH(now()) as m, SUM(total) as grandtotal
FROM tb
group BY YEAR(now()), MONTH(now())

我正在搜索如何获得今年和本月的总数，但我的总计也是去年的总数。例如，我有2018年第8个月= 20和2017年第8个月= 40的数据。它将总结所有。所以我的总数将是60而不是20。

example sqlfiddle

Answer 1

仅按分组使用月-将按月级别给您总和，但是如果按分组也按年将显示逐年总计和

SELECT MONTH(now()) as m, SUM(total) as grandtotal
FROM tb
group BY MONTH(now())

Answer 2

Based on answer from last time

select year(date) as y, month(date) as m, sum(paid) as p
from table
where year(now()) = year(date) and month(now()) = month(date)
group by year(date), month(date)

请注意，如果表定义不同，则列名也可能会不同。

Answer 3

您应该按字段的值而不是常量进行分组。

SELECT MONTH(YourDateField) as m, SUM(total) as grandtotal
FROM tb
WHERE YEAR(YourDateField) = YEAR(now())
GROUP BY YEAR(YourDateField), MONTH(YourDateField)

重新发布：SQl查询以按月/年汇总金额

3 个答案: