我有一组看起来像这样的Json数据文件
[
{"client":"toys",
"filename":"toy1.csv",
"file_row_number":1,
"secondary_db_index":"4050",
"processed_timestamp":1535004075,
"processed_datetime":"2018-08-23T06:01:15+0000",
"entity_id":"4050",
"entity_name":"4050",
"is_emailable":false,
"is_txtable":false,
"is_loadable":false}
]
我用以下自定义分类器Json Path创建了一个Glue Crawler
$[*]
Glue返回正确的模式,其中列已正确标识。
但是,当我在Athena上查询数据时,所有数据都在第一列中,其余列为空。
如何使数据按其列分布?
谢谢!
答案 0 :(得分:0)
这是与Hive相关的问题。我建议两种方法。首先,您可以在Athena中使用如下结构数据类型创建新表:
CREATE EXTERNAL TABLE `example`(
`row` struct<client:string,filename:string,file_row_number:int,secondary_db_index:string,processed_timestamp:int,processed_datetime:string,entity_id:string,entity_name:string,is_emailable:boolean,is_txtable:boolean,is_loadable:boolean> COMMENT 'from deserializer')
ROW FORMAT SERDE
'org.openx.data.jsonserde.JsonSerDe'
STORED AS INPUTFORMAT
'org.apache.hadoop.mapred.TextInputFormat'
OUTPUTFORMAT
'org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat'
LOCATION
's3://example'
TBLPROPERTIES (
'CrawlerSchemaDeserializerVersion'='1.0',
'CrawlerSchemaSerializerVersion'='1.0',
'UPDATED_BY_CRAWLER'='example',
'averageRecordSize'='271',
'classification'='json',
'compressionType'='none',
'jsonPath'='$[*]',
'objectCount'='1',
'recordCount'='1',
'sizeKey'='271',
'transient_lastDdlTime'='1535533583',
'typeOfData'='file')
然后您可以按以下方式运行查询:
SELECT row.client, row.filename, row.file_row_number FROM "example"
第二,您可以按如下所示重新设计json文件,然后再次运行Crawler。在此示例中,我使用了“每行单个JSON记录”格式。
{"client":"toys","filename":"toy1.csv","file_row_number":1,"secondary_db_index":"4050","processed_timestamp":1535004075,"processed_datetime":"2018-08-23T06:01:15+0000","entity_id":"4050","entity_name":"4050","is_emailable":false,"is_txtable":false,"is_loadable":false},
{"client":"toys2","filename":"toy2.csv","file_row_number":1,"secondary_db_index":"4050","processed_timestamp":1535004075,"processed_datetime":"2018-08-23T06:01:15+0000","entity_id":"4050","entity_name":"4050","is_emailable":false,"is_txtable":false,"is_loadable":false}