我有这个功能：
template <typename T>
struct is_bananas<T, value_void_t<T::config::num_items>>
: std::true_type {};
Public Function nextBlock(featureBlockObj As FeatureBlock, endFeatureNumber As Variant) As FeatureBlock
Dim downstreamFeatureNumber As Variant
'get the feature number that this endpoint connects to
downstreamFeatureNumber = featureBlockObj.connectedFeatureNumber(endFeatureNumber)
'if it connects to a feature number, look that feature number up in blockDict
If isNumericNonBlank(downstreamFeatureNumber) Then
Set nextBlock = blockDict(downstreamFeatureNumber)
'if it does not connect, this is the last block in the sequence
Else
Set nextBlock = Nothing
End If
End Function
是字典； blockDict是用户定义的类。
此行：
FeatureBlock抛出错误：
Set nextBlock = blockDict(downstreamFeatureNumber)
我已验证以下内容：
Object required.
作为downstreamFeatureNumber中的密钥存在blockDict是blockDict(downstreamFeatureNumber)类型的对象那我为什么不能使用FeatureBlock将blockDict()引用分配给nextBlock？
答案 0 :(得分：1)
很明显，blockDict(downstreamFeatureNumber)没什么，这是您的问题。在尝试分配给nextBlock之前，您需要先对其进行限定（如果不应该发生，那么这将是一个完全不同的问题-不是VBA问题）。
If isNumericNonBlank(downstreamFeatureNumber) _
AND (Not (blockDict(downstreamFeatureNumber) Is Nothing)) Then