我有一个数据集,显示了每个类别的消费者(来过一次,两次,3次,4次,5次等的消费者)的来宾数量和收入。
我要获取上述表格的查询是:
SELECT number_of_trans, COUNT(*) AS guest_count, SUM(amount) AS revenue
FROM customer_counting
GROUP BY number_of_trans
ORDER BY number_of_trans
现在,我想将guest_count和收入加起来,并想将它们归为以下类别:1、2、3、4、5-7和8 +。
所以实际上1,2,3和4将保持不变,但我将在第5-7行以及第8行及以后的行中求和。
我该怎么做?我想要的表如下(不用担心值的准确性):
我希望我的问题得到理解。
答案 0 :(得分:1)
使用case
和一个子查询(或CTE):
SELECT (CASE WHEN number_of_trans < 5 THEN CAST(number_of_trans as varchar)
WHEN number_of_trans < 8 THEN '5-7'
ELSE '8+'
END) as grp,
SUM(guest_count) as guest_count, SUM(revenue) as revenue
FROM (SELECT number_of_trans, COUNT(*) AS guest_count, SUM(amount) AS revenue
FROM customer_counting
GROUP BY number_of_trans
) x
GROUP BY grp
ORDER BY MIN(number_of_trans);
答案 1 :(得分:0)
戈登提案的简单形式:
SELECT
CASE WHEN number_of_trans < 5 THEN cast(number_of_trans as varchar)
WHEN number_of_trans < 8 THEN '5-7'
ELSE '8+'
END as freq_band,
COUNT(*) AS guest_count,
SUM(amount) AS revenue
FROM customer_counting
GROUP BY CASE WHEN number_of_trans < 5 THEN cast(number_of_trans as varchar)
WHEN number_of_trans < 8 THEN '5-7'
ELSE '8+'
END
ORDER BY freq_band