您好,我在分配课程时都尝试获取特定课程的截止日期,因此我有3种类型的表,可以在这3个表中为用户分配课程,而我有userid列,因此在我的课程表中必须满足条件,但如果我仅给出一个条件,则它不起作用
这是我的查询:
$sql1="SELECT cm.id as cmid,c.id as cid,c.fullname,c.startdate,c.timecreated,c.theme,cm.instance,asg.duedate,asd.duedate,sca.duedate FROM mdl_course c LEFT JOIN mdl_course_modules cm ON c.id=cm.course LEFT JOIN mdl_ppc_assigncourses_group asg On asg.courseid=c.id LEFT JOIN mdl_ppc_assigncourses_dep asd On asd.courseid=c.id LEFT JOIN mdl_ppc_singlecourse_assign sca On sca.courseid=c.id where c.category != 0 and requested='0' AND cm.id!='' AND asg.userid='2101' and sca.userid= '2101' and asd.userid= '2101' GROUP BY cm.id HAVING COUNT(*) > 0";
在该查询中,如果我仅保留一种where c.category != 0 and requested='0' AND cm.id!='' AND asg.userid='2101'
这样的条件,则它正在获取一门课程,我也具有课程形式asg.userid,因此如果我添加它则不起作用
我正在尝试获取该特定课程的截止日期,但对于第一门课程,我得到的第二个截止日期的正确截止日期显示为默认日期(1970-01-01)
这是我的代码:
<?php
require_once($CFG->dirroot . '/mod/scorm/lib.php');
require_once($CFG->dirroot . '/mod/scorm/locallib.php');
require_once($CFG->dirroot . '/course/lib.php');
global $DB;
$id = $USER->id;
$stmt = $DB->get_records_sql("
SELECT asg.asgid,asg.courseid,asg.groupid,asg.duedate FROM mdl_ppc_assigncourses_group asg
JOIN mdl_ppc_group_users pgu ON asg.groupid = pgu.group_id
WHERE pgu.userid = '$id' AND asg.status='1'and pgu.status='1'
UNION SELECT asd.acdid,asd.courseid,asd.depid,asd.duedate FROM mdl_ppc_assigncourses_dep asd
JOIN mdl_ppc_dep_user pdu ON asd.depid = pdu.department
WHERE pdu.userid = '$id' AND asd.status='1' and pdu.status='1'
UNION SELECT mpsa.scid,mpsa.courseid,mpsa.depid,mpsa.duedate FROM mdl_ppc_singlecourse_assign mpsa LEFT JOIN mdl_course c ON mpsa.courseid=c.id where mpsa.userid = '$id' and mpsa.status='1'");
$cids = '';
foreach ($stmt as $value) {
$cids[] = $value->courseid;
}
//print_r($cids);
$sql1="SELECT cm.id as cmid,c.id as cid,c.fullname,c.startdate ,c.timecreated ,c.theme ,cm.instance,asg.duedate ,asd.duedate ,sca.duedate
FROM mdl_course c
LEFT JOIN mdl_course_modules cm ON c.id=cm.course AND cm.id!=''
LEFT JOIN mdl_ppc_assigncourses_group asg On asg.courseid=c.id AND asg.userid='2101'
LEFT JOIN mdl_ppc_assigncourses_dep asd On asd.courseid=c.id and asd.userid= '2101'
LEFT JOIN mdl_ppc_singlecourse_assign sca On sca.courseid=c.id and sca.userid= '2101'
where c.category != 0 and requested='0'
GROUP BY cm.id
HAVING COUNT(*) > 0";
if ($cids != '') {
$cids = implode(',', $cids);
$sql1 .= " and cid in ($cids)";
}
$courses = $DB->get_records_sql($sql1);
if (sizeof($courses) && $cids != '') {
foreach ($courses as $row) {
echo $row->duedate;
}
}
有人可以帮我解决吗
谢谢。
答案 0 :(得分:2)
如果将where子句用于过滤左连接表列,则此操作将用作内部连接..
您应在子句的相关左联接中移动这些条件
$sql1="SELECT cm.id as cmid
,c.id as cid
,c.fullname
,c.startdate
,c.timecreated
,c.theme
,cm.instance
,asg.duedate
,asd.duedate
,sca.duedate
FROM mdl_course c
LEFT JOIN mdl_course_modules cm ON c.id=cm.course AND cm.id!=''
LEFT JOIN mdl_ppc_assigncourses_group asg On asg.courseid=c.id AND asg.userid='2101'
LEFT JOIN mdl_ppc_assigncourses_dep asd On asd.courseid=c.id and asd.userid= '2101'
LEFT JOIN mdl_ppc_singlecourse_assign sca On sca.courseid=c.id and sca.userid= '2101
where c.category != 0 and requested='0' '
GROUP BY cm.id
HAVING COUNT(*) > 0";