Question

def concordance(string, search_term, width=80):
    offset = 0
    indexes = []

  while offset < len(string):
    try:

        position = string[offset:].lower().index(search_term.lower())
    except ValueError:

        break
    if position:
        indexes.append(position + offset)

        offset += position + len(search_term)
   return tuple(string[index-width:index+width+len(search_term)] 

string = 'The relationship between beef and beef broth, is not like the 
relationship between beef and beef-broth, a simpler extraction and 
condensation; rather, as Einstein goes on, it is like the relationship 
between our overcoat and the ticket given us when we check our overcoat. In 
other words, human perception involves coding even more than crude 
sensing.just as a map-maker colors a nation purple not because it is purple 
but because his code demands it."

当我尝试用search_term为“ and”调用调和函数时，结果不仅返回“ and”，而且还返回其中包含and的单词，例如“ demand”。我如何更改代码，使其仅返回“和”？

Answer 1

如评论中所述

：您可以尝试使用re module。在这里，我只会在search_term以外的字符包围着您的[a-zA-Z0-9_]的情况下（不确定是否最适合您的意图...）：

import re

def concordance(strg, search_term, width=5):
    ret = []
    # \W Matches any character which is not a word character. 
    # ~ anything that is not [a-zA-Z0-9_]
    rgx = re.compile('\W{}\W'.format(search_term))
    match_end = 0
    while True:
        match = rgx.search(strg, match_end)
        if match is None:
            break
        ret.append(strg[match.start()+1-width:match.end()-1+width])
        match_end = match.end()
    return ret


print(concordance(strg, 'and'))  
# ['beef and beef', 'beef and beef', 'tion and\ncond', 'coat and the ']

使用python中的corcordance视图查找关键字

1 个答案: