Question

您好，我有一个折叠包装，默认情况下其显示状态为true（我无法更改）一个模态组件在打开时需要显示False。我认为将defaultOpen道具设置为“ false”会将Display设置为false。但这行不通。我做错了什么？这是代码：

我的折叠包装器：

import React, { Component } from "react";
import ChevronUp from "react-feather/dist/icons/chevron-up";
import ChevronDown from "react-feather/dist/icons/chevron-down";
import { Collapse } from "reactstrap";
import "./style.scss";

class CollapseWrapper extends Component {
  constructor(props) {
    super(props);

    this.state = {
      display:
        props.defaultOpen === undefined ? true : props.defaultOpen,
      title: this.props.title,
    };
  }

  toggleContainer = () => {
    this.setState(prevState => ({
      display: !prevState.display,
    }));
  };

  render() {
    const { display, title } = this.state;
    return (
      <div>
        <button type="button" onClick={this.toggleContainer}>
          <div className="title-container">
            {display ? (
              <ChevronUp className="chevron" />
            ) : (
              <ChevronDown className="chevron" />
            )}

            <h2>{title}</h2>
          </div>
        </button>
        <Collapse isOpen={this.state.display}>
          {this.props.children}
        </Collapse>
      </div>
    );
  }
}

export default CollapseWrapper;

我的模态：

import React from "react";
import { Modal } from "reactstrap";
import CollapseWrapper from "./CollapseWrapper";

class Mymodal extends Component {
  constructor(props) {
    super(props);
    this.state = {};
  }

  render() {
    const { isOpen } = this.props;
    return (
      <Modal size="xxl" isOpen={isOpen} toggle={this.close}>
        <CollapseWrapper defaultOpen="false" title="More détails">
          Some content...
        </CollapseWrapper>
      </Modal>
    );
  }
}

export default Mymodal;

Answer 1

在按钮上的onClick事件中使用箭头功能

替换

onClick={this.toggleContainer}

至

onClick={() => this.toggleContainer()}

Answer 2

您应该在大括号{}中传递布尔值，而不是字符串。正确defaultOpen={false} 错误的defaultOpen="false"

<CollapseWrapper defaultOpen={false} title="More détails">
   Some content...
</CollapseWrapper>

Answer 3

我认为，您可以使用组件生命周期方法componentWillReceiveProps(nextProps)解决此问题。当componentWillReceiveProps时，再次设置您的display状态。

解决方案：

componentWillReceiveProps(nextProps) {
   if (nextProps.defaultOpen !== this.state.display) {
     this.setState({ ...this.state, display: nextProps.defaultOpen });
   }
}

如何在ReactJS中的组件中传递道具

3 个答案: