Question

我有一个带有varchar列的表，如下所示：

    +---------+-----------+
    | FruitId | FruitName |
    +---------+-----------+
    |     123 | Apple     |
    |     123 | Mango     |
    |     145 | Mango     |
    +---------+-----------+

查询

select * from Fruits with (nolock) where FruitId  like '123 something something%'

预期结果：

123     Apple
123     Mango

查询

select * from Fruits with (nolock) where FruitName  like 'Apple something something%'

预期结果：

123     Apple

但是上面的查询不起作用，为什么？

任何帮助将不胜感激。

更新：

select * from Fruits with (nolock) where FruitId  like '123 something something%' 
             or FruitName like 'Apple something something%'

即使这不起作用，希望我们必须将这两列连接起来。

Answer 1

如果我正确理解了您的问题，则应在如下所示的where子句中使用OR

查询＃1

select * from Fruits with (nolock) where FruitId  like '123 Apple%'

应该是

select * from Fruits with (nolock) where FruitId  like '123' OR FruitName like 'Apple'

查询＃2

select * from Fruits with (nolock) where FruitName  like 'Apple 123%'

应该像这样

select * from Fruits with (nolock) where FruitName  like 'Apple' OR FruitId like  '123'

Answer 2

您可以通过将两列都连接起来来做到这一点

select * from Fruits with (nolock) where CONCAT(FruitId , ' ', FruitName ) 
         like '123 Apple%' OR CONCAT(FruitName , ' ', FruitId) like 'Apple 123%'

Answer 3

尝试以下

DECLARE @T TABLE
(
    FruitId VARCHAR(50), 
    FruitName VARCHAR(50)
)
DECLARE @Src VARCHAR(50)='Apple 123'

INSERT INTO @T 
VALUES(123, 'Apple'),
(123, 'Mango'),
(145, 'Mango');

SELECT
    *
    FROM @T
        WHERE FruitId like LTRIM(RTRIM(SUBSTRING(@Src,1,CHARINDEX(' ',@Src))))+'%'
            OR
            FruitName like LTRIM(RTRIM(SUBSTRING(@Src,1,CHARINDEX(' ',@Src))))+'%'

Answer 4

连接值以一次与LIKE进行比较：

CREATE TABLE fruits(FruitId VARCHAR(256), FruitName VARCHAR(256));
INSERT INTO fruits VALUES(123, 'Apple'),(123, 'Mango'),(145, 'Mango');

SELECT FruitId, FruitName 
FROM fruits 
WHERE FruitId+' '+FruitName like '123 Apple%' OR FruitName+' '+FruitId like '123 Apple%'

Answer 5

尝试一下...

用户输入：123 something-something...

查询1

SELECT * 
FROM   fruits WITH (nolock) 
WHERE  '123 something-something...' LIKE Concat(fruitid, '%')

结果

+---------+-----------+
| FruitId | FruitName |
+---------+-----------+
|     123 | Apple     |
|     123 | Mango     |
+---------+-----------+

用户输入：Apple something-something...

查询2

SELECT * 
FROM   fruits WITH (nolock) 
WHERE  'Apple something-something...' LIKE Concat(fruitname, '%')

结果

+---------+-----------+
| FruitId | FruitName |
+---------+-----------+
|     123 | Apple     |
+---------+-----------+

SQL搜索包含第一个字符串

5 个答案: