我有一个熊猫数据框,我想替换值
temp2 <- gather(temp, ' ', val, -kt)
filter(temp2, val>0) %>%
ggplot(aes(fct_rev(kt), val, fill = ` `)) +
geom_col(position = 'fill', color='black') +
geom_text(aes(label = val), position = position_fill(vjust = 0.5), size=3) +
scale_y_continuous(labels = scales::percent_format())+theme_bw()+
labs(x='Canton', y='Percentage')+coord_flip()+ scale_fill_grey(start = 0.9, end = .5)+
guides(fill=guide_legend(title="Label", reverse=T))
我尝试过
itemsets = [["26"], ["51", "28", "27"], ["50"], ["8"], ["81","26",
15"], ["10"], ["81"]]
support = [0.06421, 0.00123, 0.04112, 0.0112, 0.12097, 0.08123,
0.0021334]
df = pd.DataFrame()
df["itemsets"]= itemsets
df["support"] = support
我会得到以下结果:
df.replace("26","dog")
答案 0 :(得分:0)
创建用于替换的字典,然后对get
使用嵌套列表推导-如果值不匹配,则返回旧的:
d = {'26':'dog'}
df["itemsets"] = [[d.get(y, y) for y in x] for x in df['itemsets']]
print (df)
itemsets
0 [dog]
1 [51, 28, 27]
2 [50]
3 [8]
4 [81, dog, 15]
5 [10]
6 [81]