我有下表,其中a1是可以重复的年龄。 g1是性别,其中0代表男性,1代表女性。
| a1 | g1|
.................
| 40 | 0 |
| 48 | 1 |
| 47 | 0 |
| 52 | 0 |
| 64 | 1 |
| 50 | 1 |
| 63 | 1 |
| 57 | 0 |
我想按年龄显示男性和女性的数量,并每行显示男性和女性的总数。我没有得到想要的结果。
| a1 |male|female|total|
-----------------------------
| 40 | 120 | 80 | 200 |
| 48 | 130 | 90 | 220 |
| 47 | 140 | 70 | 210 |
| 52 | 150 | 40 | 190 |
| 64 | 160 | 45 | 205 |
| 50 | 170 | 30 | 200 |
| 63 | 180 | 30 | 210 |
| 57 | 190 | 50 | 240 |
答案 0 :(得分:1)
在以下情况下使用案例:
select a1 as age, sum(case when g1=0 then 1 end) as male, sum(case when g1=1 then 1 end) as female, sum(case when g1 in (1,0) then 1 end) as total
group by a1
答案 1 :(得分:1)
您可以使用按年龄分组的select case和sum()进行选择性汇总
SELECT a1 age
, SUM(CASE WHEN g1=0 THEN 1 END) male
, sum(CASE WHEN g1=1 THEN 1 END) female
, SUM(CASE WHEN g1=0 THEN 1 END) +sum(CASE when g1=1 THEN 1 END) total
FROM my_table
GROUP BY a1