Question

我有这样的字符串：

str1 = "Information name: Wen Moyes address: Mcity."
str2 = "resume Name : Sam Win Father's name: Dean address"
str3 = "Father's name: Dan. Acknowledge"
str4 = "Father's Name: Joe Cena Name :- John Cena"

我想从Name之后的每个字符串中提取名称。如果字符串包含Father's name，则应忽略该部分，而仅查找name

我的预期输出是：

Wen Moyes
Sam Win
None
John Cena

我尝试过的事情：

我在regex以下使用

re.findall(r'name\s*:(\s*\w*\s\w*)', str1.lower())

这给我的输出为：

[' wen moyes']
[' sam win', ' dean address']
[' dan']
[' joe cena']

我该如何处理？
有没有不使用正则表达式的替代方法？

谢谢！

Answer 1

一种选择是对Father's进行负向后看，然后将Name:与可选的空格/破折号匹配，然后捕获以下(\w+ \w+)：

str1 = "Information name: Wen Moyes address: Mcity."
str2 = "resume Name : Sam Win Father's name: Dean address"
str3 = "Father's name: Dan. Acknowledge"
str4 = "Father's Name: Joe Cena Name :- John Cena"

pattern = re.compile(r"(?<!Father's )[Nn]ame ?:-? (\w+ \w+)")
for str in [str1, str2, str3, str4]:
    print(re.findall(pattern, str))

https://regex101.com/r/Gp5PDr/1

如何提取某些模式后出现的字符串？

1 个答案: