Question

我的坐标如下所示

lat=9.0516854 
longi= 76.5360752

我需要做的是，从具有ID的位置集中找到最近的经度和纬度。就像

{8: [{'id': 8, 'latitude': '9.042418900000001', 'longitude': '76.5861815'}], 9: [{'id': 9, 'latitude': '34.1047016', 'longitude': '-118.3338668'}], 10: [{'id': 10, 'latitude': '8.5469144', 'longitude': '76.8792397'}]}

谁能帮助我，谢谢你

Answer 1

要正确计算地球上各点之间的距离，需要使用Haversine公式。使用Python，您可以这样编码：

from math import cos, asin, sqrt

def distance(lat1, lon1, lat2, lon2):
    p = 0.017453292519943295
    a = 0.5 - cos((lat2-lat1)*p)/2 + cos(lat1*p)*cos(lat2*p) * (1-cos((lon2-lon1)*p)) / 2
    return 12742 * asin(sqrt(a))

lat=9.0516854 
longi= 76.5360752

base_cordinate = {'lat': lat, 'lon': longi}

d = {8: [{'id': 8, 'latitude': '9.042418900000001', 'longitude': '76.5861815'}], 9: [{'id': 9, 'latitude': '34.1047016', 'longitude': '-118.3338668'}], 10: [{'id': 10, 'latitude': '8.5469144', 'longitude': '76.8792397'}]}

def closest(data, v):
    return min(data, key=lambda p: distance(v['lat'],v['lon'],p['lat'],p['lon']))

cord_list = []

for k,v in d.items():

    new_lat = float(v[0]['latitude'])
    new_long = float(v[0]['longitude'])

    cord_dict = {'lat' : new_lat, 'lon' : new_long}
    cord_list.append(cord_dict)

closest_cordinate = closest(cord_list, base_cordinate)

# To Get the id

def fetch_id(base_dict, closest):

    for key, val in d.items():

        if float(val[0]['latitude']) == closest_cordinate['lat'] and float(val[0]['longitude']) == closest_cordinate['lon']:
            return val[0]['id']

closest_cordinate['id'] = fetch_id(d, closest_cordinate)

print(closest_cordinate)

如何找到距路线的最短距离（Python），

1 个答案: