Question

我有一个文件，其中包含：

，我想将其读入列表列表，其中：

[[1,3,3],[1,5,6],[2,4,9],[2,4,8],[4,5,7]]

我尝试过：

def main():
    filename = open("mytext.txt","r",encoding = "utf-8")
    file = filename
    lst = []

    for line in file:
        line = line.strip().split()
        lst.append(line)

    for val in range(len(lst)):
        val = int(lst[val])

    print(lst)

main()

但是我说错了

TypeError: int() argument must be a string, a bytes-like object or a number, not 'list'

希望对此有所帮助。

Answer 1

我们可以使用numpy.genfromtxt

import numpy as np
answer = np.genfromtxt('Test.txt', dtype=np.int64).tolist()

Answer 2

使用列表推导和readlines

In [107]: with open('mytext.txt', encoding='utf-8') as file_pointer:
     ...:     lst = [[int(j) for j in i.split()] for i in file_pointer.readlines()]

列表推导通常比其他方法快得多且可读性强。

上述方法类似于

In [111]: with open('mytext.txt', encoding='utf-8') as file_pointer:
     ...:     lst = []
     ...:     for i in file_pointer.readlines():
     ...:         inner_lst = []
     ...:         for j in i.split():
     ...:             inner_lst.append(int(j))
     ...:
     ...:         lst.append(inner_lst)
     ...:

In [112]: lst
Out[112]: [[1, 3, 3], [1, 5, 6], [2, 4, 9], [2, 4, 8], [4, 5, 7]]

Answer 3

在您的代码中，尝试替换：

for val in range(len(lst)):
    val = int(lst[val])

具有：

result = []

for row in lst:
    row_list = []
    for i in row.split():
        val = int(i.strip())
        row_list.append(var)
    result.append(row_list)

或更简洁：

result = [[int(i.strip()) for i in row.split()] for row in lst]

将文本文件内容读入整数列表

3 个答案: