我已经设计了一个红色字体动词短语并将其输出为HTML的代码。
from __future__ import unicode_literals
import spacy,en_core_web_sm
import textacy
import codecs
nlp = en_core_web_sm.load()
sentence = 'The author is writing a new book. The dog is barking.'
pattern = r'<VERB>?<ADV>*<VERB>+'
doc = textacy.Doc(sentence, lang='en_core_web_sm')
lists = textacy.extract.pos_regex_matches(doc, pattern)
with open("my.html","w") as fp:
for list in lists:
search_word = (list.text)
fp.write(sentence.replace(search_word, '<span style="color: red">{}</span>'.format(search_word)))
当前输出
The author **is writing** a new book. The dog is barking.The author is writing a new book. The dog **is barking.**
句子被重复两次,首先是写作,最后是吠叫。
预期输出:
The author **is writing** a new book. The dog **is barking.**
在发送到列表检查之前,我是否必须对句子进行标记处理?请帮忙吗?
答案 0 :(得分:1)
找到了另一种更合乎逻辑的方法。与其替换整个句子,不如替换具有模式的句子。
with open("my.html","w") as fp:
for list in lists:
search_word = (list.text)
containing_sentence = [i for i in sentence.split('.') if str(search_word) in str(i)][0]
fp.write(containing_sentence.replace(search_word, '<span style="color: red">{}</span>'.format(search_word)))
以上代码将分别写出句子。如果要以句子的形式进行操作,请将修改内容附加到列表中,然后将其加入,然后按如下所示写入文件。
mod_sentence = []
for list in lists:
search_word = (list.text)
containing_sentence = [i for i in sentence.split('.') if str(search_word) in str(i)][0]+'.'
mod_sentence.append(containing_sentence.replace(search_word, '<span style="color: red">{}</span>'.format(search_word)))
with open("my.html","w") as fp:
fp.write(''.join(mod_sentence))
希望这会有所帮助!干杯!